Re: $var invokes function?

2009-08-08 Thread BuraphaLinux Server
Not exactly what you asked for, but works the same: #! /bin/bash today() { date } printf "today is %s\n" "$(today)" exit 0 It is easier to just use $(date) directly though. On 8/8/09, jscripter wrote: > > Hi, > > Is it possible to create a variable whose value is determined by a function? >

read -t0 doesn't pick up waiting characters

2009-08-08 Thread Chris F.A. Johnson
(Using 4.0.28(2)-release on Linux and 4.0.24(0)-release on FreeBSD.) Given this script: delay=0 read -sn1 v read -sn1 -t "$delay" w read -sn1 -t "$delay" x if I press the up arrow, which generates '\e[A', I would have expected $w to contain '[' and $x to contain 'A'. However