Re: bash 4.4.19

On Wed, Sep 19, 2018 at 08:38:59AM +0300, Евгений Мёдов wrote: >for i in {1..5}; do >A A var${i}=$RANDOM >done What you want is an array. See . for i in 1 2 3 4 5; do var[i]=$RANDOM done echo "${var[1]}" declare -p var

bash 4.4.19

A Bash version 4.4.19. Assignment does not work A for i in {1..5}; do A A var${i}=$RANDOM done A bash: var1=: command not found bash: var2=: command not found bash: var3=: command not found bash: var4=: command not found bash: var5=: command not found