On Sun, May 11, 2008 at 02:01:29PM -0400, Paul Jarc wrote:
> Felix Schwarz <[EMAIL PROTECTED]> wrote:
> > I'm not able to specify an interpreter in a shebang line if the path
> > to this interpreter contains spaces.
>
> It's actually the kernel that interprets that line, not bash.
Hi Bob, hi Paul,
thanks for your detailed explanations. So I agree that this is not a bash bug
;-)
Maybe in ten years we will see a Un*x release which will allow the use of
spaces in the shebang line *dreaming*.
thanks again
fs
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On Sun, May 11, 2008 at 12:37:12PM -0600, Bob Proulx wrote:
> Felix Schwarz wrote:
> > I'm not able to specify an interpreter in a shebang line if the path
> > to this interpreter contains spaces.
>
> That is correct. It is part of the implementation of the Berkeley #!
> exec(2) h
Felix Schwarz wrote:
> I'm not able to specify an interpreter in a shebang line if the path
> to this interpreter contains spaces.
That is correct. It is part of the implementation of the Berkeley #!
exec(2) hack and as such is now simply the way things are and have
been for many
Felix Schwarz <[EMAIL PROTECTED]> wrote:
> I'm not able to specify an interpreter in a shebang line if the path
> to this interpreter contains spaces.
It's actually the kernel that interprets that line, not bash. The
historical behavior is that space separates the interpreter from
