Chet Ramey wrote:
Think it through. A variable is not set until it has been assigned a
value. Giving a variable an attribute (in this case, the `local'
attribute) without assigning a value means that the variable is still
unset. For example,
Unless it was set in the global cont
Linda, I think the second example is more clear if made more explicit, like:
set -o posix
f() { local POSIXLY_CORRECT; unset POSIXLY_CORRECT; shopt -p -o posix; }
f
On 6/18/16 7:59 PM, Linda Walsh wrote:
> Grisha Levit wrote:
>> The manual references these values being set, not just declared, so maybe
>> should check for invisible_p?
> ---
> Why? I.e. what were you wanting to happen?
Think it through. A variable is not set until it has been assigned a
valu
Thanks for the advise!
That did it. The command is working fine now with the following setup:
currentuser="$(id -u -n)"
OPTS=(-q -avz --delete -e 'ssh -i /home/'$currentuser'/.ssh/id_rsa'
--rsync-path='sudo rsync')
SRC=(/etc/nginx/)
RSYNC_CMD=(rsync)
for h in balancer0{1..2} ; do
DST=$curren
On Fri, Jun 17, 2016 at 01:57:33PM -0700, dp...@realtruck.com wrote:
> OPTS=(-q -avz --delete -e \'ssh -i /home/$currentuser/.ssh/id_rsa\'
> --rsync-path=\'sudo rsync\')
You want:
OTPS=(-q -avz --delete -e "ssh -i /home/$currentuser/.ssh/id_rsa"
--rsync-path="sudo rsync")
OPTS+=( whatever
