Hum, on my system, I get the message you are expecting. Transcript:
$ uname -a
Linux it-johnmckown-linux 3.19.1-201.fc21.x86_64 #1 SMP Wed Mar 18
04:29:24 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux
[tsh009@it-johnmckown-linux junk]$ bash --version
GNU bash, version 4.3.33(1)-release (x86_64-redhat-li
It was fixed a year ago:
https://github.com/hughsie/PackageKit/commit/b8f5de2e0ceaf7424e4e2c94adc46fa06eefce73
On Tue, Mar 31, 2015 at 1:04 PM, Robin A. Meade
wrote:
> ok, thanks. If I run bash with no startup files, I get expected output.
>
> With my regular start-up files:
>
> $ declare -f c
ok, thanks. If I run bash with no startup files, I get expected output.
With my regular start-up files:
$ declare -f command_not_found_handle
command_not_found_handle ()
{
runcnf=1;
retval=127;
[ ! -S /var/run/dbus/system_bus_socket ] && runcnf=0;
[ ! -x /usr/libexec/packagekitd ]
Cannot reproduce with these versions:
dualbus@yaqui:~/local/src/gnu/bash$ "a nonexistent command name with spaces"
bash: a nonexistent command name with spaces: command not found
dualbus@yaqui:~/local/src/gnu/bash$
GNU bash, version 4.4.0(1)-devel (x86_64-unknown-linux-gnu)
dualbus@yaqui:~$ "a n
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-redhat-linux-gnu'
-DCONF_VENDOR='redhat' -DLOCALEDIR='/usr/share/locale' -
On Tue, Mar 31, 2015 at 07:24:09PM +0300, Filimonov Vadim wrote:
[...]
> But I can't understand why
> echo *
Read the bash manual, section 'Pathname Expansion'.
--
Eduardo Bustamante | https://dualbus.me/
Hello.You are right.Thank You!31.03.2015, 19:11, "Eduardo A. Bustamante López" :Not a bug.On Tue, Mar 31, 2015 at 06:04:53PM +0300, Filimonov Vadim wrote:[..] filimonov@filimonov:~/bashbug/bash-4.3$ read -u63 LINE <(echo "*");echo $LINE bash: read: `/dev/fd/63': not a valid identifier ABOUT-NLS a
Hello, Greg!Thank you. It's really my mistake, sorry.Good explanation.But I can't understand whyecho *prints listing of directory?31.03.2015, 19:06, "Greg Wooledge" :On Tue, Mar 31, 2015 at 06:04:53PM +0300, Filimonov Vadim wrote: filimonov@filimonov:~/bashbug/bash-4.3$ read -u63 LINE <(echo "*")
Not a bug.
On Tue, Mar 31, 2015 at 06:04:53PM +0300, Filimonov Vadim wrote:
[..]
> filimonov@filimonov:~/bashbug/bash-4.3$ read -u63 LINE <(echo "*");echo $LINE
> bash: read: `/dev/fd/63': not a valid identifier
> ABOUT-NLS aclocal.m4 alias.c alias.h alias.o array.c arrayfunc.c arrayfunc.h
> arr
On Tue, Mar 31, 2015 at 06:04:53PM +0300, Filimonov Vadim wrote:
> filimonov@filimonov:~/bashbug/bash-4.3$ read -u63 LINE <(echo "*")
> bash: read: `/dev/fd/63': not a valid identifier
You are missing a < sign here. You probably wanted:
read LINE < <(echo "*")
It is not safe to assume that the
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKA
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