Configuration Information [Automatically generated, do not change]:
Machine: powerpc
OS: linux-gnu
Compiler: gcc -I/usr/src/packages/BUILD/bash-3.2
-L/usr/src/packages/BUILD/bash-3.2/../readline-5.2
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='powerpc'
-DCONF_OSTYPE='linux-gnu' -DCONF_M
Dolphin06 <[EMAIL PROTECTED]> writes:
> I dont get it right, i always display only the first one, and i dont know how
> to write a scalar variable.
> I tried like this :
> ssh [EMAIL PROTECTED] script2 -f "[EMAIL PROTECTED]"
This passes every element of my_array as a separate argument. Also, ssh
I dont get it right, i always display only the first one, and i dont know how
to write a scalar variable.
I tried like this :
ssh [EMAIL PROTECTED] script2 -f "[EMAIL PROTECTED]"
It's not changing anything.
I m using bash.
Thank you.
Stephane Chazelas wrote:
>
> On Tue, Dec 09, 2008 at 09:14:51
On bash 3.2 patchlevel 048 (and earlier) there appears to be problems in vi
mode and prompts containing escape characters (such as to get bold text).
To reproduce:
Enter vi editing mode set -o vi
Set the following prompt:
export PS1="[\!] [EMAIL PROTECTED]:\w>"
Type "one two three four five six
I did the change but i still have only the first element displaying. I must
say that i m using ssh to call script2 on remote server so maybe it is the
problem :
script1
ssh [EMAIL PROTECTED] script2 -f [EMAIL PROTECTED] -d [EMAIL PROTECTED]
and on script2 it only echoes the first element of bo
On Tue, Dec 09, 2008 at 09:14:51AM -0500, Chet Ramey wrote:
> >
> > Hello i would like to pass an array to my script command line argument, but
> > only the first element of the array is displayed. Here is my process :
> >
> > script1:
> > my_array=(el1 el2 el3)
> > script2 -f $my_array
>
> You
Dolphin06 wrote:
> Hello,
> So how can i pass the entire array, i m new to shell scripting so i do not
> really understand when you talk about unsubscripted word expansion
Since programs only take a list of strings as arguments, you have to expand
the array to a list of values. The "[EMAIL PROTEC
Hello,
So how can i pass the entire array, i m new to shell scripting so i do not
really understand when you talk about unsubscripted word expansion
Thank you for helping.
Chet Ramey wrote:
>
>>
>> Hello i would like to pass an array to my script command line argument,
>> but
>> only the first
>
> Hello i would like to pass an array to my script command line argument, but
> only the first element of the array is displayed. Here is my process :
>
> script1:
> my_array=(el1 el2 el3)
> script2 -f $my_array
You're only passing the first element of the array to script2. An
unsubscripted
Hello i would like to pass an array to my script command line argument, but
only the first element of the array is displayed. Here is my process :
script1:
my_array=(el1 el2 el3)
script2 -f $my_array
script2:
while getopts ":f:" opt ; do
case $opt in
f ) arr="$OPTARG" ;;
esac
done
echo "ar
Cheng Renquan wrote:
On Tue, Dec 9, 2008 at 11:40 AM, Chet Ramey <[EMAIL PROTECTED]> wrote:
Investigate patch 44. It should fix this.
From where?
From
ftp://ftp.gnu.org/gnu/bash/bash-3.2-patches/
Or please tell a bash repository version, I'll test it.
Chet
--
``The lyf so s
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