That is probably what I was missing for a very long time.
Xtian.
On 2016-04-27 01:00, Elias Mårtenson wrote:
The Dyalog language reference guide contains all the Dyalog stuff:
http://docs.dyalog.com/14.1/Dyalog%20APL%20Language%20Reference.pdf
In particular, ⍤ is described on page 146, and ⌸
Hi,
If you are talking about Dyalog, you can take a look for example here:
http://help.dyalog.com/14.1/Content/Language/Introduction/Language%20Elements.htm
Christian Robert writes:
> where are you taking the definition of various functions like ?
>
> power operator ?
>
> dieresis jot ? like:
The Dyalog language reference guide contains all the Dyalog stuff:
http://docs.dyalog.com/14.1/Dyalog%20APL%20Language%20Reference.pdf
In particular, ⍤ is described on page 146, and ⌸ on page 139.
The formal ISO APL specification can be downloaded here:
http://www.math.uwaterloo.ca/~ljdickey/apl-
where are you taking the definition of various functions like ?
power operator ?
dieresis jot ? like: (⊂⍤1) z,⍪z (I really don't know what it is doing)
I see no references anywhere on the web. None in apl2 manual, none in Dyalog
manual.
how can I learn thoses ... without a manual and/or som
On Wed, Apr 27, 2016 at 5:02 AM, Elias Mårtenson wrote:
> So, I wanted to simply take a string of characters, and create a list of
> each character and the number of occurrences of each character in that
> string.
Indeed it could be written in Dyalog very succinctly as
⊣,∘≢⌸ but I would write it p
I was reading about the Dyalog "key" operator ⌸. It's certainly a useful
function, and something that should probably be added to GNU APL, in my
opinion.
As always when thinking about useful additions to GNU APL, I wanted to try
to do some things that ⌸ can do, without having access to it.
So, I
A defect was introduced in revision 722.
In libapl.cc, line 410, a parameter "false" should be added.
FredW
I agree that this seems like a bug. Your example works in NARS2000 and
Dyalog. To make it work in GNU APL I currently have to do an extra
enclose:
({⊂⊂⍵}⍤1)z,⍪z←⍳4
┌→──┐
│┌→──┐ ┌→──┐ ┌→──┐ ┌→──┐│
││1 1│ │2 2│ │3 3│ │4 4││
│└───┘ └───┘ └───┘ └───┘│
└∊──
Given the following definition:
* z←⍳4*
I was trying to generate the following:
┏→━━┓
┃┏→━━┓ ┏→━━┓ ┏→━━┓ ┏→━━┓┃
┃┃1 1┃ ┃2 2┃ ┃3 3┃ ┃4 4┃┃
┃┗━━━┛ ┗━━━┛ ┗━━━┛ ┗━━━┛┃
┗∊━━┛
I attempted to do the following:
* (⊂⍤1) z,⍪z*
I expected this to work, b
