thank you very much, I now understand how it work !
looks so easy for you ;-) and so hard for me :-(
Xtian.
On 2016-03-01 21:43, Elias Mårtenson wrote:
On 2 March 2016 at 10:28, Christian Robert mailto:christian.rob...@polymtl.ca>> wrote:
IOTA ← {∘.,/⍳¨⍵}
yes, it does the trick (you
On 2 March 2016 at 10:28, Christian Robert
wrote:
> IOTA ← {∘.,/⍳¨⍵}
>
> yes, it does the trick (you are really good btw)
>
I don't consider myself good. :-)
Anyway, it's quite simple. Let me break it down:
First of all, ¨⍳⍵ will simply create the individual iotas:
* ⍳¨2 3 4*
┌→
I see, but what is the "/" doing ?
Xtian
{⍳¨⍵} 1
┌───┐
│┌→┐│
││1││
│└─┘│
└∊──┘
{⍳¨⍵} 1 2
┌2┐
│┌→┐ ┌2──┐│
││1│ │1 2││
│└─┘ └───┘│
└∊┘
{⍳¨⍵} 1 2 3
┌3┐
│┌→┐ ┌2──┐ ┌3┐│
││1│ │1 2│ │1 2 3││
│└─┘ └───┘ └─┘│
└∊┘
{∘.,/⍳¨⍵} 1
IOTA ← {∘.,/⍳¨⍵}
yes, it does the trick (you are really good btw)
but I had to disclose the result
IOTA 2 3 5
┌─┐
│┌5──┐│
│2┌3┐ ┌3┐ ┌3┐ ┌3┐ ┌3┐││
│││1 1 1│ │1 1 2│ │1 1 3│ │1 1 4│ │1 1 5│││
│3└
Looking at it further, I realise you need do disclose the result in order
to make them equivalent:
* IOTA ← {⊃∘.,/⍳¨⍵}*
Regards,
Elias
On 2 March 2016 at 10:19, Elias Mårtenson wrote:
> I don't know about a loop, but wouldn't this do the same thing?
>
> *IOTA ← {∘.,/⍳¨⍵}*
>
> Regards,
I don't know about a loop, but wouldn't this do the same thing?
*IOTA ← {∘.,/⍳¨⍵}*
Regards,
Elias
On 2 March 2016 at 09:57, Christian Robert
wrote:
> I have this function,
>
> ∇IOTA[⎕]∇
> ∇
> [0] z←IOTA v
> [1] z←⍳↑v
> [2] v←1↓,v
> [3] Loop: →(0=⍴v)/0
> [4] z←z∘.,⍳↑v
> [
I have this function,
∇IOTA[⎕]∇
∇
[0] z←IOTA v
[1] z←⍳↑v
[2] v←1↓,v
[3] Loop: →(0=⍴v)/0
[4] z←z∘.,⍳↑v
[5] v←1↓v
[6] →Loop
∇
]boxing 24
IOTA 0
┌⊖┐
│0│
└─┘
IOTA 10
┌10──┐
│1 2 3 4 5 6 7 8 9 10│
└┘
IOTA 2 3
┌3──
