Jay,
Thank you. This made me aware of the fact that I still don't understand
this. You are right that the rank is zero, shown by the fact that ⍴,/1
2 3returns an empty result:
*8⎕CR ⍴,/1 2 3*
┌⊖┐
│0│
└─┘
Can you explain to me why that is the case? When I look at the result from ,/1
2 3 it
On 31 January 2014 17:37, Elias Mårtenson wrote:
> 8⎕CR ,/1 2 3 4
> ┌─┐
> │┌→──┐│
> ││1 2 3 4││
> │└───┘│
> └∊┘
I just have one comment to add to Kacper's excellent explanation: a
useful thing to remember about this implementation of *reduction* is
that it always *re
