I believe that the Payment Protocol works that way, the merchant broadcast
the Tx.
El 10/06/2014 13:23, "Chris D'Costa" escribió:
> I wonder if Raul is mistakenly under the impression that the transaction
> only reaches the Bitcoin network via Alice? In which case the premise of
> this "attack" i
On Sat, Jun 07, 2014 at 12:02:36AM +0200, Raúl Martínez wrote:
> I dont know if this attack is even possible, it came to my mind and I will
> try to explain it as good as possible.
>
> Some transacions keep unconfirmed forever and finally they are purged by
> Bitcoin nodes, mostly due to the lack
Whenever you do a reissuing of a transaction that didn't go through
earlier, you should make sure to reuse one of the inputs for it. That
guarantees that both cannot confirm simultaneously.
On Sat, Jun 7, 2014 at 12:21 AM, Raúl Martínez wrote:
> Alice does not intercept the transaction, she only
Alice does not intercept the transaction, she only saves it and expect that
it will not be confirmed (because has 0 fee for example).
Also using the Payment Protocol I believe that Alice is the only person
that can relay Bob's transaction.
Source: https://github.com/bitcoin/bips/blob/master/bip-0
>From what I know, Alice does not know to which node Bob will broadcast the
transaction. Therefore, Alice cannot intercept the transaction and prevent
the rest of the network from seeing it.
Toshi
On Fri, Jun 6, 2014 at 3:02 PM, Raúl Martínez wrote:
> I dont know if this attack is even possib
I dont know if this attack is even possible, it came to my mind and I will
try to explain it as good as possible.
Some transacions keep unconfirmed forever and finally they are purged by
Bitcoin nodes, mostly due to the lack of fees.
Example:
-
Alice is selling a pizza to Bob, Bob is no
I dont know if this attack is even possible, it came to my mind and I will
try to explain it as good as possible.
Some transacions keep unconfirmed forever and finally they are purged by
Bitcoin nodes, mostly due to the lack of fees.
Example:
-
Alice is selling a pizza to Bob, Bob is no
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