On Tuesday, June 05, 2012 12:00:25 AM Mike Koss wrote:
> I don't understand how your proposal will work for decentralized pools -
> can you explain it more concretely?
>
> What would the new block header look like?
For example (just a draft; in reality, merged mining would probably be
I don't understand how your proposal will work for decentralized pools -
can you explain it more concretely?
What would the new block header look like?
What is required for a share to to be earned?
What is required for a block to be valid (added to Block Chain)?
I don't think I understand what
As I understand the attack, the attacker gets compensated for the shares
they earn, but the pool will be denied any valid blocks found. The
attacker DOES NOT have access to the Bitcoins earned in the unreported
block (only the mining pool has access to the Coinbase address and
transactions in the
On Monday, June 04, 2012 8:49:48 PM Mike Koss wrote:
> As I understand the attack, the attacker gets compensated for the shares
> they earn, but the pool will be denied any valid blocks found. The
> attacker DOES NOT have access to the Bitcoins earned in the unreported
> block (only the mining poo
On Monday, June 04, 2012 1:43:42 AM Peter Vessenes wrote:
> Does it have asymmetric payoff for an attacker, that is, over time does it
> pay them more to spend their hashes attacking than just mining?
That depends on the pool's reward scheme. Some complicated forms are capable
of getting "bonus"
On Sat, Jun 2, 2012 at 8:52 PM, Luke-Jr wrote:
> Analysis, comments, constructive criticism, etc welcome for the following:
>
> ==Background==
> At present, an attacker can harm a pool by intentionally NOT submitting
> shares
> that are also valid blocks. All pools are vulnerable to this attack,
Analysis, comments, constructive criticism, etc welcome for the following:
==Background==
At present, an attacker can harm a pool by intentionally NOT submitting shares
that are also valid blocks. All pools are vulnerable to this attack, whether
centralized or decentralized and regardless of rew
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