On Aug 7, 7:47 pm, [EMAIL PROTECTED] (Chris Cosner) wrote:
> I've re-read perlref and have been trying to tease an answer out of the
> Perl Cookbook.
>
> If you put a hash reference into an array
> push @array, \%hash;
> you do not store any actual hash data in the array.
> So if you change th
Aha. Many thanks.
Now I'm on the right track (see Anonymous Data in the Perl Cookbook, ch.
11).
Mr. Shawn H. Corey wrote:
Chris Cosner wrote:
If you put a hash reference into an array
push @array, \%hash;
you do not store any actual hash data in the array.
So if you change the hash, then
> I've re-read perlref and have been trying to tease an answer out of the
> Perl Cookbook.
>
> If you put a hash reference into an array
> push @array, \%hash;
> you do not store any actual hash data in the array.
> So if you change the hash, then later pull the hash reference from the
> array
Chris Cosner wrote:
If you put a hash reference into an array
push @array, \%hash;
you do not store any actual hash data in the array.
So if you change the hash, then later pull the hash reference from the
array and access it, you get changed data.
push @array, { %hash };
This creates an
I've re-read perlref and have been trying to tease an answer out of the
Perl Cookbook.
If you put a hash reference into an array
push @array, \%hash;
you do not store any actual hash data in the array.
So if you change the hash, then later pull the hash reference from the
array and access i
