--- "Randal L. Schwartz" <[EMAIL PROTECTED]> wrote:
> > "Rene" == Rene Verharen <[EMAIL PROTECTED]> writes:
>
> Rene> The (sub)dirs I want to create are input from a form, so I had to
> Rene> change your example a little because
>
> Rene> my @dir=qw($FORM{'dir'});
>
> No no no! This is
> "Rene" == Rene Verharen <[EMAIL PROTECTED]> writes:
Rene> The (sub)dirs I want to create are input from a form, so I had to
Rene> change your example a little because
Rene> my @dir=qw($FORM{'dir'});
No no no! This is a security hole, unless you've also validated the
data using code y
> "Roger" == Roger C Haslock <[EMAIL PROTECTED]> writes:
Roger> In this case I think you drop into shell
Roger> `mkdir -p $fullpath`;
This is dangerous, unportable, and far less efficient than necessary.
See "perldoc File::Path", which I found by looking in the standard
library using "perld
In this case I think you drop into shell
`mkdir -p $fullpath`;
# And check for errors!!!
- Roger -
- Original Message -
From: "Rene Verharen" <[EMAIL PROTECTED]>
To: "Beginners-CGI List" <[EMAIL PROTECTED]>
Sent: Saturday, January 19, 2002 5:01 PM
Sub
At 19-1-2002 15:29 -0600, Shawn wrote:
>Try something like this:
>
>my $string=$homDir;
>my @dir=qw(directory somedir someotherdir yetanotherdir);
>for(@dir) {
> $string.=$_;
> mkdir $string, 0755;
>}
>
>untested
Tested and approved, but...
The (sub)dirs I want to create are input from a fo
Hi,
Can someone please point me in the right direction ?
In a script I'm trying to write I need to create a new directory. This new
directory looks something like /directory/somedir/someotherdir/yetanotherdir.
What I do now is :
mkdir "$homeDir/directory", 0755";
mkdir "$homeDir/dire
