I don't know that I'd agree with the assessment
@ = ordered list
% = unordered list
That's a bit confusing. It's true that a hash (or associative array) uses
its own sort order unless you use the 'sort' option.
But an array is a simple list of elements, whereas a hash is an assoc
I can see where you're coming from on this. However the most obvious reason is that
perl has no relationship in scalar context between @somename and %somename.
Your question regarding the "special" $ is not germane to this concept. Each element
of the array is a separate scalar variable, accesse
In a message dated 12/18/2002 12:13:38 PM Eastern Standard Time,
[EMAIL PROTECTED] writes:
>
> Anyway, perhaps one of you syntactical thought police could give me some
> insights to the rational. I find it very confusing that the $ and @
> characters
> are supposed to be used interchangeably
@var is an array
$var is a scalar
$var[0] is also a scalar even though is an array element.
@var[0] is an array which contains more array elements, but in this case it
contains just a single element.
To create an array slice with more elements, you'll need something like
@var[0 .. n]
You need to
My understanding is that it's simpler than that. @ means list and $ means
scalar, and essentially one element in a list is really a scalar. $foo[0]
gets you the first scalar from the list @foo.
$count = scalar(@foo);
gets you a count of all the elements in the list. At least to me the @/$
Hello:
I have been fairly confused on the intermixing of array naming standards. If I
understand correctly, the @array syntaxt is used to refer to the whole array,
while $array[n] is refered to specific elements.
In my thinking, it would have been less confusing to use @array[n] to address
speci
