Hi perlatwork,
On Saturday 01 Jan 2011 13:21:29 perl wrote:
> use strict;
> use warnings;
> use YAML;
> use HTML::Tree;
> use LWP::UserAgent;
> my $ua = LWP::UserAgent->new;
> my $response =
> $ua->get('http://www.raaga.com/channels/hindi/moviedetail.asp?mid=H002927')
> ; my $content1 = $response-
On Sun, Jan 2, 2011 at 00:06, Octavian Rasnita wrote:
> Better say that bottom-post is an old habit (and advanced programmers usually
> have old habits and not the newbies) and that the rules are enforced by the
> advanced programmers because they can help the others, and they want to
> everyon
On Sun, Jan 2, 2011 at 9:39 AM, Raymond Wan wrote:
> An extension to your reasoning is that there aren't just two groups of
> users on this list -- advanced and newbies -- but multiple levels.
> Beginners who don't follow the advanced programmers' rules may have
> questions that intermediate progr
From: "Raymond Wan" On Sun, Jan 2, 2011 at 00:06, Octavian
Rasnita wrote:
> Better say that bottom-post is an old habit (and advanced programmers usually
> have old habits and not the newbies) and that the rules are enforced by the
> advanced programmers because they can help the others, and th
From: "Brandon McCaig"
On Sun, Jan 2, 2011 at 9:39 AM, Raymond Wan wrote:
> An extension to your reasoning is that there aren't just two groups of
> users on this list -- advanced and newbies -- but multiple levels.
> Beginners who don't follow the advanced programmers' rules may have
> questions
Hi all, I'm new to Perl. The only other language I know is
Matlab/Octave and I'm still working my way around Linux. I am using
Shlomi Fish's tutorial on perl until I get the llama book. I'm stuck
on section [4.1. "+=" and friends ] [1]. I don't really understand the
part "$a *= 2; $b += 1;" What is
That means: $a = $a * 2
i.e take the existing value of $a, multiply it with 2 and reassign it to $a
Cheers,
Parag
On Sun, Jan 2, 2011 at 4:00 PM, J. S. John wrote:
> Hi all, I'm new to Perl. The only other language I know is
> Matlab/Octave and I'm still working my way around Linux. I am usi
Sorry, forgot to reply-to-all again :(
$a *= 2;
Basically translates to this:
$a = $a * 2;
just like
$b += 1;
translates to:
$b = $b + 1;
On Sun, Jan 2, 2011 at 7:00 PM, J. S. John wrote:
> Hi all, I'm new to Perl. The only other language I know is
> Matlab/Octave and I'm still working my
On 11-01-02 07:07 PM, Sheppy R wrote:
Sorry, forgot to reply-to-all again:(
$a *= 2;
Basically translates to this:
$a = $a * 2;
just like
$b += 1;
translates to:
$b = $b + 1;
This is true of almost every binary operator. Some of the weird ones:
$x ||= 0; # if $x is zero, undef, or an
> "JSJ" == J S John writes:
JSJ> Hi all, I'm new to Perl. The only other language I know is
JSJ> Matlab/Octave and I'm still working my way around Linux. I am using
JSJ> Shlomi Fish's tutorial on perl until I get the llama book. I'm stuck
JSJ> on section [4.1. "+=" and friends ] [1].
$a *= $b means the same thing as $a = $a * $b.
On Sun, 02 Jan 2011 19:00:05 -0500, J. S. John
wrote:
Hi all, I'm new to Perl. The only other language I know is
Matlab/Octave and I'm still working my way around Linux. I am using
Shlomi Fish's tutorial on perl until I get the llama book. I'm
Has anybody here been using Net::Cassandra?
I used but sometime found it run with problems.
Not sure it's me or this module or the cassandra server's problem.
Thanks.
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Hi All
I am planning to give Perl training to my juniors in my
team. They are new to Perl. Could anyone please send me any Perl
training materials with exercises, or links, which I can refer to?
Please send me good suggestions also for training.
Thanks & Regards
Sunita
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