On 5/9/06, Smith, Derek <[EMAIL PROTECTED]> wrote:
my (@key2,$value2) = 0;
This statement is odd. It's making a new array with a single element
(which element is zero). I think you mean something like this:
my(@key2);
my $value2 = 0;
$key2[$value2++] = (grep /mirror/gi, `lvdis
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of
Tom Phoenix
Sent: Wednesday, May 10, 2006 6:35 PM
To: Smith, Derek
Cc: Perl Beginners
Subject: Re: using Perl grep to populate a scalar
On 5/9/06, Smith, Derek <[EMAIL PROTECTED]> wrote:
> if
On 5/9/06, Smith, Derek <[EMAIL PROTECTED]> wrote:
if (/(?)vg00/) {
That doesn't look right. Why is that question mark inside parentheses?
If Perl doesn't complain about that pattern, maybe it should.
Hope this helps!
--Tom Phoenix
Stonehenge Perl Training
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-Original Message-
From: Smith, Derek
Sent: Tuesday, May 09, 2006 5:22 PM
To: Perl Beginners
Subject: using Perl grep to populate a scalar
All,
I am trying to populate a scalar (ideally a hash) using a Perl grep but
it is not working. I even tried to use an array and no data was
All,
I am trying to populate a scalar (ideally a hash) using a Perl grep but
it is not working. I even tried to use an array and no data was pushed.
use strict;
use warnings;
my @lvs;
my @lvaray = qx(bdf);
foreach (@lvaray) {
if (/(?)vg00/) {
push @lvs, (split)[0]
}
}
