On Wed, 02 Feb 2005 20:37:54 +, mike <[EMAIL PROTECTED]> wrote:
> No the problem was that this ( with the quote in the "right" place) was
> giving me what I didnt want.
>
> this is the code
> @value=param();
> shift (@value);
> shift (@value);
> pop (@value);
> print @value;
> foreach $value (
On Wed, 2005-02-02 at 09:23 -0500, Wiggins d'Anconia wrote:
> mike wrote:
> > Am I right in thinking that if you double quote the seperator in split
> > the seperator is added to the array ie:
> >
> > @array3=split(/"\t/",$value4); would add \t to the end of @array3 while
>
> As you have written
On Wed, 2005-02-02 at 12:54 -0500, Jay wrote:
> On Wed, 02 Feb 2005 12:39:17 +, mike <[EMAIL PROTECTED]> wrote:
> > Am I right in thinking that if you double quote the seperator in split
> > the seperator is added to the array ie:
> >
> > @array3=split(/"\t/",$value4); would add \t to the end
On Wed, 02 Feb 2005 12:39:17 +, mike <[EMAIL PROTECTED]> wrote:
> Am I right in thinking that if you double quote the seperator in split
> the seperator is added to the array ie:
>
> @array3=split(/"\t/",$value4); would add \t to the end of @array3 while
>
> @array3=split(/\t/,$value4); would
mike wrote:
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/"\t/",$value4); would add \t to the end of @array3 while
As you have written it above I get a syntax error:
String found where operator expected at ./test.pl lin
Am I right in thinking that if you double quote the seperator in split
the seperator is added to the array ie:
@array3=split(/"\t/",$value4); would add \t to the end of @array3 while
@array3=split(/\t/,$value4); would not
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-m
