on Tue, 14 May 2002 16:43:42 GMT, [EMAIL PROTECTED] (Joe Mecklin)
wrote:
> ($connect_id = ars_Login($server, $userid, $password)) || die
> "Can't login:$ars_errstr\n";
If you use 'or' instead of '||' you won't need the silly looking
outer '()'.
> (%properties = ars_GetField($con
tml
Hope this helps.
(BTW: Also, your question probably belongs on the ARSperl mailing list.)
Ross
-Original Message-
From: MECKLIN, JOE (ASI) [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, May 14, 2002 12:44 PM
To: '[EMAIL PROTECTED]'
Subject: reference to hash
All,
I've been f
All,
I've been fighting this for a while and I'm afraid I can't see the trees for
the forest now (yes, I know that's bass-ackwards)...
I'm using ARS.pm to access the Remedy product. One function -
ars_GetField() - returns a reference to a hash, and what I've been trying to
read isn't sinking in
On Thu, 8 Nov 2001, Lisa Neclos wrote:
> I am getting the following error when trying to run this. I'm trying to
> pass a hash as a reference to the subroutine.
>
> ERROR - Type of Arg 1 to each must be hash (not private variable)
>
> my $ref_hash ;
> %hash = ("sky", "blue", "grass", "green", "a
On Nov 8, Lisa Neclos said:
>sub print {
I wouldn't name a function print() if I were you.
>while (my($key, $val) = each($ref_hash)) { #while hash has another
Since $ref_hash is a reference to a hash, and each() needs a hash, use
%$ref_hash, or %{ $ref_hash }.
--
Jeff "japhy" Pinyan [E
I am getting the following error when trying to run this. I'm trying to
pass a hash as a reference to the subroutine.
ERROR - Type of Arg 1 to each must be hash (not private variable)
my $ref_hash ;
%hash = ("sky", "blue", "grass", "green", "apple", "red") ;
$ref_hash = \%hash ;
sub print {
wh
