Thank you Paul, Randal!!! :)
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--- EriK W <[EMAIL PROTECTED]> wrote:
> Thanks! Paul, you are really good tutor, It is much clear for me now,
Thank you. That's a high compliment.
> But I think I still can't easily distinguish the list and scalar
> context.
That's a common problem.
To oversimplify, a scalar context is a situa
Thanks! Paul, you are really good tutor, It is much clear for me now,
But I think I still can't easily distinguish the list and scalar context.
Like here, you say it is a list context, just because we are using the
"sort" or because the ()[0] ?
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Paul <[EMAIL PROTECTED]> wrote:
>here, it's not doing anything magical. Putting parens around it and
>subscripting
>
> ($b =~ /=(\d+)/)[0]
>
>means treat the resulting list of matches as an array, and give me
>element zero. Thus, it's getting the first matched set of digits in $b
>that follow an e
--- EriK W <[EMAIL PROTECTED]> wrote:
> Thanks , Paul, but I think I can't make it straight part of because
> my broken English , so it seems make sense for me, but
Better to try than sit quietly and be confused. =o)
> > In
> >
> > ($b =~ /=(\d+)/)[0] <=> ($a =~ /=(\d+)/)[0]
> >
> > the <=> i
Thanks , Paul, but I think I can't make it straight part of because my
broken English , so it seems make sense for me, but
"Paul" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> --- EriK W <[EMAIL PROTECTED]> wrote:
> > Hi guys,
> >
> > I have a question ma
--- Michael Fowler <[EMAIL PROTECTED]> wrote:
> On Fri, Jul 20, 2001 at 09:01:55AM -0700, Paul wrote:
> > I don't know the behavior for certain on a final return of zero,
> > but I don't think it does anything, which likely means that later
> > things may or may not reverse their order based on c
On Fri, Jul 20, 2001 at 09:01:55AM -0700, Paul wrote:
> I don't know the behavior for certain on a final return of zero, but I
> don't think it does anything, which likely means that later things may
> or may not reverse their order based on comparisons of other pairs, so
> that the end result is
--- EriK W <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> I have a question maybe about "sort" or regular expression,
>
> @new = sort {($b =~ /=(\d+)/)[0] <=> ($a =~ /=(\d+)/)[0]|| uc($a)
> cmp uc($b) } @old;
>
> I don't really understand this /=(\d+)/ [0] thing, expecially that
> "=" , what does
Hi guys,
I have a question maybe about "sort" or regular expression,
@new = sort {($b =~ /=(\d+)/)[0] <=> ($a =~ /=(\d+)/)[0]|| uc($a) cmp
uc($b) } @old;
I don't really understand this /=(\d+)/ [0] thing, expecially that "=" ,
what does that mean?
Thanks!
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