Nigel Peck - MIS Web Design wrote:
Sorry for the delay in responding.
The Perl 6 format is what I was thinking, just have to wait for that :)
For more info about Perl 6 syntax, see http://dev.perl.org/
Quantum::Superpositions sounds pretty cool.
It's very cool. Every scalar can be in superpositi
From: zsdc [mailto:[EMAIL PROTECTED]
> Sent: 30 August 2003 18:16
> To: Nigel Peck - MIS Web Design
> Cc: [EMAIL PROTECTED]
> Subject: Re: or operator
>
>
> Nigel Peck - MIS Web Design wrote:
>
> > In Perl can I say:
> >
> > if this = that or that or tha
Nigel Peck - MIS Web Design wrote:
In Perl can I say:
if this = that or that or that
instead of saying:
if this = that or this = that or this = that
Not yet, but good point. In Perl 6 you'll be able to write:
if $x == 1|2|7
but now there's only:
if $x == 1 or $x == 2 or $x == 7
Maybe yo
Nigel Peck wrote:
>
> In Perl can I say:
>
> if this = that or that or that
>
> instead of saying:
>
> if this = that or this = that or this = that
No.
What do you want?
if ($this == $that) {
:
}
elsif ($this == $that) {
:
}
elsif ($this == $that) {
:
}
else {
:
}
Typeo should be $my not #my
-Original Message-
From: Paul Kraus [mailto:[EMAIL PROTECTED]
Sent: Friday, August 29, 2003 1:55 PM
To: 'Nigel Peck - MIS Web Design'; [EMAIL PROTECTED]
Subject: RE: or operator
If ($my eq $this) || (#my eq $this2) {
code;
}else{
If ($my eq $this) || (#my eq $this2) {
code;
}else{
more code;
}
HTH
-Original Message-
From: Nigel Peck - MIS Web Design [mailto:[EMAIL PROTECTED]
Sent: Friday, August 29, 2003 1:50 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: or operator
In Perl can I say
In Perl can I say:
if this = that or that or that
instead of saying:
if this = that or this = that or this = that
Cheers,
Nigel
Managing Director
MIS Web Design
http://www.miswebdesign.com/
Administrator
AccessifyForum.com
http://www.accessifyforum.com/
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On Thu, Jun 07, 2001 at 06:39:32PM -0400, Travis Smith wrote:
>
> Either you or I (or maybe both us) have a really dirty mind.
>
>
> Isn't that like:
> (true != 0)
Nope, that's ($you || $I || ($you && $I)), which reduces to simply ($you ||
$I).
> Y
