"John W. Krahn" schreef:
> BTW $$_[0] is usually written as $_->[0].
I think it is a pity that O::Deparse() doesn't do this:
$ perl -MO=Deparse -e '$$_[0] = 1'
$$_[0] = 1;
-e syntax OK
$ perl -MO=Deparse -e '$_->[0] = 1'
$$_[0] = 1;
-e syntax OK
--
Affijn, Ruud
"Gewoon is een tijger."
--
T
JAaronAnderson.com wrote:
Ok, thanks guys for posting, I am posting from within my GoogleGroup
Account.
Ergo my comment...
let's not be critical and get down to the code!
the code I was asking about was ::
map { $_ = $$_[0] } @userlist;
I dont understand it fully but I got what I wanted to get
Ok, thanks guys for posting, I am posting from within my GoogleGroup
Account.
Ergo my comment...
let's not be critical and get down to the code!
the code I was asking about was ::
map { $_ = $$_[0] } @userlist;
I dont understand it fully but I got what I wanted to get done with
the following::.
> Message du 27/09/08 15:41
> De : "John W. Krahn"
> A : "Perl Beginners"
> Copie à :
> Objet : Re: join operator for arrays question
>
>
> JAaronAnderson.com wrote:
> > =pod
> > Hey fellow GoogleGroup Brothers & Sisters,
>
> I
JAaronAnderson.com wrote:
=pod
Hey fellow GoogleGroup Brothers & Sisters,
I hate to disappoint you but this is not a "GoogleGroup", this is a
mailing list controlled by perl.org.
I am hoping to ask you all a quick Perl intermediate logic question…
I have called an obj command which returns
On Fri, 2008-09-26 at 13:15 -0700, JAaronAnderson.com wrote:
> my @userlist = $obj->command_ok(qw/user list/, "","","");
> # it then returns this info I think
> # “emailHandle”, “User FullName”
> # because it shows Array elements in memory
> # foreach of them but not the mapped qw word list hm
=pod
Hey fellow GoogleGroup Brothers & Sisters,
I am hoping to ask you all a quick Perl intermediate logic question…
I have called an obj command which returns what I think is a multi-
dimensional array like so
=cut
my @userlist = $obj->command_ok(qw/user list/, "","","");
# it then returns this in
