On Fri, Aug 19, 2016 at 2:22 PM Chas. Owens wrote:
> Truth. If you are checking in lots of things exist a hashset might be a
> better way to go:
>
> my %hashset = map { ($_ => undef) } (3,1,4,2,9,0);
>
> my $found = exists $hashset{4} || 0;
> my $not_found = exists $hashset{10} || 0;
>
> By sett
Truth. If you are checking in lots of things exist a hashset might be a
better way to go:
my %hashset = map { ($_ => undef) } (3,1,4,2,9,0);
my $found = exists $hashset{4} || 0;
my $not_found = exists $hashset{10} || 0;
By setting the value of the hash to be undef, you take up less space than
s
But does it need to be an array. Rethink into hash and life could be a little
bit easier...
Wags ;)
WagsWorld
Hebrews 4:15
Ph: 408-914-1341
On Aug 18, 2016, 19:41 -0700, kp...@freenet.de, wrote:
> Thanks for all the replies.
> Yes I found List::Util is a useful toolset.
>
>
> On 2016/8/19 10:00,
Thanks for all the replies.
Yes I found List::Util is a useful toolset.
On 2016/8/19 10:00, Chas. Owens wrote:
The any function from List::Util will also do what you want.
perldoc List::Util
http://perldoc.perl.org/List/Util.html#any
my $found = any { $_ == 4 } (3, 1, 4, 2, 9, 0); # true
my
On Thu, Aug 18, 2016 at 9:39 PM wrote:
> Hello,
>
> What's the better way to decide if an element exists in an array?
> Something like what ruby does,
>
> irb(main):001:0> x=[3,1,4,2,9,0]
> => [3, 1, 4, 2, 9, 0]
> irb(main):002:0> x.include? 4
> => true
> irb(main):003:0> x.include? 10
> => fals
Here is one approach using a perl repl.
re.pl
$ my @x = qw(3 1 4 2 9 0)
$VAR1 = 3;
$VAR2 = 1;
$VAR3 = 4;
$VAR4 = 2;
$VAR5 = 9;
$VAR6 = 0;
$ grep {$_ == 4} @x and 'true'
grep {$_ == 10} @x and 'true' or 'false'
On Thu, Aug 18, 2016 at 7:35 PM, wrote:
> Hello,
>
> What's the better way to decide
On 19 August 2016 at 13:45, Kent Fredric wrote:
>if ( first { $item == 4 } @items ) {
>say "Yes";
>}
>
Ugh, my bad.
if ( first { $_ == 4 } @items ) {
say "Yes";
}
--
Kent
KENTNL - https://metacpan.org/author/KENTNL
--
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On 19 August 2016 at 13:35, wrote:
>
> What's the better way to decide if an element exists in an array?
> Something like what ruby does,
>
> irb(main):001:0> x=[3,1,4,2,9,0]
> => [3, 1, 4, 2, 9, 0]
> irb(main):002:0> x.include? 4
> => true
> irb(main):003:0> x.include? 10
> => false
> irb(main)
Hello,
What's the better way to decide if an element exists in an array?
Something like what ruby does,
irb(main):001:0> x=[3,1,4,2,9,0]
=> [3, 1, 4, 2, 9, 0]
irb(main):002:0> x.include? 4
=> true
irb(main):003:0> x.include? 10
=> false
irb(main):004:0> quit
I tried searching but found nothin
