On Monday 20 September 2010 09:49:27 rahul patil wrote:
> Hello all,
>
> below is sample code i have written.Is it right way to declare ar4 which is
> concatenation of ar and ar1
>
> #!/usr/bin/perl
> @ar = {"rahul","patil"};
You shouldn't use { ... } for arrays (this is not C). Use:
my @ar = (
> "PK" == Parag Kalra writes:
PK> #!/usr/bin/perl
PK> use strict;
PK> use warnings;
PK> my @ar = ("rahul","patil");
PK> my @ar1 = ("nitin");
PK> my @ar4;
PK> push @ar4, (@ar, @ar1);
PK> print "@ar4";
it is nice that you are trying to help but your code can be
better. there is
On Mon, Sep 20, 2010 at 1:30 PM, Chaitanya Yanamadala <
dr.virus.in...@gmail.com> wrote:
> @ar = ("rahul","patil");
> @ar1 = ("nitin");
> @ar4 = (@ar,@ar1);
>
> the only problem is u should not define the array with this { } it should
> be defined within this brackets ();
>
> Chaitanya
>
>
This wo
@ar = ("rahul","patil");
@ar1 = ("nitin");
@ar4 = (@ar,@ar1);
the only problem is u should not define the array with this { } it should be
defined within this brackets ();
Chaitanya
On Mon, Sep 20, 2010 at 1:19 PM, rahul patil
wrote:
> Hello all,
>
> below is sample code i have written.Is it
#!/usr/bin/perl
use strict;
use warnings;
my @ar = ("rahul","patil");
my @ar1 = ("nitin");
my @ar4;
push @ar4, (@ar, @ar1);
print "@ar4";
Cheers,
Parag
On Mon, Sep 20, 2010 at 12:49 AM, rahul patil
wrote:
> Hello all,
>
> below is sample code i have written.Is it right way to declare ar4 whi
Hello all,
below is sample code i have written.Is it right way to declare ar4 which is
concatenation of ar and ar1
#!/usr/bin/perl
@ar = {"rahul","patil"};
@ar1 = {"nitin"};
@ar4 = {...@ar,@ar1};
print @ar4[2];
if yes, why it is not printing output as nitin on my system
--
Regards,
Rahul Patil
