On Wed, Apr 20, 2011 at 03:58, Saran wrote:
> Here is the program
>
> use strict;
> use warnings;
>
> my ($div,$reminder) = ÷_now(20,4);
> print "Dividend: $div\nReminder: $reminder\n";
>
> sub divide_now {
> my ($a,$b) = @_;
>
> my ($s,$n);
> for($n=1;;$n++) {
>
On Wed, Apr 20, 2011 at 7:58 AM, Saran wrote:
> Here is the program
>
> use strict;
> use warnings;
>
> my ($div,$reminder) = ÷_now(20,4);
Please don't call subs with &; It'll bite you in the arse eventually. You
can read why in perldoc perlsub[0], or well, this mailing list.
Brian.
[0] htt
Here is the program
use strict;
use warnings;
my ($div,$reminder) = ÷_now(20,4);
print "Dividend: $div\nReminder: $reminder\n";
sub divide_now {
my ($a,$b) = @_;
my ($s,$n);
for($n=1;;$n++) {
$d+=$b;
$s = $a - ($n*$b);
retu
> How to write a device funciton without using a '/' operator
>
> sub device_now($a, $b){
> my ($a, $b)=@;
>
>
>
> return $result;
>
> }
> &device_now(6,3);
That's "divide", not "device".
Not sure it's the solution that the professor had in mind, but you
can use exponentiation (in Pe
Hi there,
How to write a device funciton without using a '/' operator
sub device_now($a, $b){
my ($a, $b)=@;
return $result;
}
&device_now(6,3);
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
