Rob Dixon schreef:
> Mr. Shawn H. Corey wrote:
>> SELECT company, COUNT(*)
>> FROM commitCurrent
>> GROUP BY company;
>
> Someone else has personal standards for SQL! Thank you Shawn!
Do you keep a list of them? I would write it as
SELECT
c.company
, COUNT(*) AS n
FROM
commitCurrent
On Fri, 2008-08-15 at 15:57 +0100, Rob Dixon wrote:
> Mr. Shawn H. Corey wrote:
> >
> > SELECT company, COUNT(*)
> > FROM commitCurrent
> > GROUP BY company;
>
> Someone else has personal standards for SQL! Thank you Shawn!
>
> Rob
>
Personal standards? I find that to be an oxymoron and a lit
Mr. Shawn H. Corey wrote:
>
> SELECT company, COUNT(*)
> FROM commitCurrent
> GROUP BY company;
Someone else has personal standards for SQL! Thank you Shawn!
Rob
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On Fri, 2008-08-15 at 13:57 +0100, Pat Rice wrote:
> hi
> I would like know how to count multiple occurances in a sql query.
>
> eg.
>
> row would be:
> tom, tom , tom, john,pat,pat
>
> and this would produce
> tom 3
> john 1
> pat 2
>
>
> I've tried this but I am only gettting 1 back
> select
hi
I would like know how to count multiple occurances in a sql query.
eg.
row would be:
tom, tom , tom, john,pat,pat
and this would produce
tom 3
john 1
pat 2
I've tried this but I am only gettting 1 back
select count(*) from commitCurrent where company =(select distinct
company from commitCur