uot;;
I suspect the problem in the newline you get from STDIN
> And the result is only
> .yyy
Isn't it the value of $FILENAME on one line, and .yyy on the next?
> How do I concatenate $FILENAME and .yyy?
Exactly as suggested by others here on the list.
chomp $FILENAME af
You will never find time for anything.
If you want time, you must make it.
Charles Buxton
- Original Message -
From: "Craig S Monroe" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 12, 2001 5:27 PM
Subject: Re: concatenate $FILENAME and
-3558
Email pager: [EMAIL PROTECTED]
--
You will never find time for anything.
If you want time, you must make it.
Charles Buxton
- Original Message -
From: "Jennifer Pan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 12, 2001 4:49 PM
Subje
Jennifer Pan wrote:
> Hello all,
>
> I stdin a file name: xxx.txt
> and I would like to have a output file name called x.txt.yyy
>
> This is how I do it
>
> $FILENAME = ;
> $output = "$FILENAME.y";
> print "$output";
>
> And the result is
make like pacman and CHOMP IT !!! ;)
$FILENAME = ;
chomp $FILENAME;
...
-Original Message-
From: Jennifer Pan [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 12, 2001 3:49 PM
To: [EMAIL PROTECTED]
Subject: concatenate $FILENAME and .yyy
Hello all,
I stdin a file name: xxx.txt
and I
Hello all,
I stdin a file name: xxx.txt
and I would like to have a output file name called x.txt.yyy
This is how I do it
$FILENAME = ;
$output = "$FILENAME.y";
print "$output";
And the result is only
.yyy
How do I concatenate $FILENAME and .yyy?
Thank you
