Bryan Harris:
> I just ran into this today, and have no clue what's going on:
>
> % perl -e 'print 10-5.5, "\n"'
> 4.5
> % perl -e 'print 10-05.5, "\n"'
> 55
Nice catch. I would also have assumed that the '.' is stronger that the
octal-0. I still think it should be.
--
Affijn, Ruud
"Gewoon is
>> I just ran into this today, and have no clue what's going on:
>>
>> % perl -e 'print 10-5.5, "\n"'
>> 4.5
>> % perl -e 'print 10-05.5, "\n"'
>> 55
>>
>> How does 10 minus 5.5 equal 55? Obviously it's the leading zero, but I
>> can't think of any reason why it should do that...
>
> It seems
Hi Bryan Harris -
At 2005-12-03, 19:19:02 you wrote:
>
>
>I just ran into this today, and have no clue what's going on:
>
>% perl -e 'print 10-5.5, "\n"'
>4.5
>% perl -e 'print 10-05.5, "\n"'
>55
>
>How does 10 minus 5.5 equal 55? Obviously it's the leading zero, but I
>can't think of any reaso
I just ran into this today, and have no clue what's going on:
% perl -e 'print 10-5.5, "\n"'
4.5
% perl -e 'print 10-05.5, "\n"'
55
How does 10 minus 5.5 equal 55? Obviously it's the leading zero, but I
can't think of any reason why it should do that...
- B
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