John W. Krahn wrote:
SYNOPSIS
gzip [ -acdfhlLnNrtvV19 ] [-S suffix] [ name ... ]
gunzip [ -acfhlLnNrtvV ] [-S suffix] [ name ... ]
zcat [ -fhLV ] [ name ... ]
Note that the -d switch applies to gzip only. zcat by definition is
*supposed* to decompress files. (Why wo
Richard Lee wrote:
John W. Krahn wrote:
open FILE, "ls -tr | zcat -d $directory/$file |", or die qq/you
My version of zcat does not have a -d switch, what does it do on your
system? It appears that "ls -tr | " in front of zcat is superfluous?
What do you think it will do there?
John W. Krahn wrote:
open FILE, "ls -tr | zcat -d $directory/$file |", or die qq/you
My version of zcat does not have a -d switch, what does it do on your
system? It appears that "ls -tr | " in front of zcat is superfluous?
What do you think it will do there?
Just to follow up
John W. Krahn wrote:
Richard Lee wrote:
Dr.Ruud wrote:
But better stop guessing and let Richard answer.
yes, variables are particular names and later I wanted to refer back
by variable names.
However, for now I have done this so far so I just added as array
instead of breaking out by var
Richard Lee wrote:
Dr.Ruud wrote:
But better stop guessing and let Richard answer.
yes, variables are particular names and later I wanted to refer back by
variable names.
However, for now I have done this so far so I just added as array
instead of breaking out by var names..
-- code is i
Dr.Ruud wrote:
"Jenda Krynicky" schreef:
Dr.Ruud:
Richard Lee:
[$file1,$file2,$file3,$file4,$file5,$file6,$file10,$file25]
I didn't want to put them in array
since I need to use individual named variable later
And why is that?
Maybe because in the real cod
"Jenda Krynicky" schreef:
> Dr.Ruud:
>> Richard Lee:
>>> [$file1,$file2,$file3,$file4,$file5,$file6,$file10,$file25]
>>> I didn't want to put them in array
>>> since I need to use individual named variable later
>>
>> And why is that?
>
> Maybe because in the real code they are not $file1, $file2,
From: "Dr.Ruud" <[EMAIL PROTECTED]>
> Richard Lee schreef:
>
>
> > [$file1,$file2,$file3,$file4,$file5,$file6,$file10,$file25]
> > I didn't want to put them in array
> > since I need to use individual named variable later
>
> And why is that?
Maybe because in the real code they are not $file1,
Richard Lee schreef:
> [$file1,$file2,$file3,$file4,$file5,$file6,$file10,$file25]
> I didn't want to put them in array
> since I need to use individual named variable later
And why is that?
--
Affijn, Ruud
"Gewoon is een tijger."
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