On Fri, 8 Jun 2001 [EMAIL PROTECTED] wrote:
> > You get this warning because $action is undefined. Comparing undefined value
> > with something is usually unwanted, so it produces a warning.
> >
> > You could rewrite it to:
> > if (defined($action) && ($action eq 'add')) {
> >
> > or assign somet
On Fri, 8 Jun 2001 [EMAIL PROTECTED] wrote:
> why is $action undefined? i use my $action; earlier in the script
> and i thought that the statement $action = $formdata{action};
> would take care of assigning a value to $action so that it would
> not be undefined.
If formdat
>
> You get this warning because $action is undefined. Comparing undefined value
> with something is usually unwanted, so it produces a warning.
>
> You could rewrite it to:
> if (defined($action) && ($action eq 'add')) {
>
> or assign something meaningful to $action before you use it.
>
>
even when defining it as my %formdata; i still get the same error. i
believe that i have tried it as
my %formdata;
my $formdata;
the only other variable reference in that line is to $action, which has a
my statement.
On Fri, 8 Jun 2001, Peter Cline wrote:
> At 09:29 AM 6/8/01 -0500, you w
