EMAIL PROTECTED]>
Sent: Tuesday, October 23, 2001 11:40 AM
Subject: Re: Syntax for grep using regex
> On Oct 23, Clinton said:
>
> >@first25 = grep{$_->[1] eq (/^MA\d+/)} @all;
>
> You're asking about how to bind a pattern to a variable:
>
> $_->[1] =~ /^M
On Oct 23, Clinton said:
>@first25 = grep{$_->[1] eq (/^MA\d+/)} @all;
You're asking about how to bind a pattern to a variable:
$_->[1] =~ /^MA\d/
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www
Hi
I would like to use grep on an array to remove rows from an array. If I hard code a
variable it works. The regex works on its own but I can't put the two together.
@first25 = grep{$_->[1] eq (/^MA\d+/)} @all;
Help appreciated
Regards
CCJ
