But it will fail if we have spaces before $modtager = " 45247";
You should probably write like this.
#!/usr/bin/perl
$modtager = "45247";
$modtager =~ s/^\s+//g; # deletes all leading spaces in variable
$modtager =~ s/^(45)//; # guarantees match of 45
-Sharif
On 12/2/05, Alexandre Checin
unless you use this syntax :
$modtager =~s/45//g;
only the first occurence of the searched string will be replace...
so what you wrote should work fine...
BR
Mads N. Vestergaard wrote:
Hi Everybody,
I have a script where I need to replace 45 in the beginning, with
nothing in a variable...
On Fri, Dec 02, 2005 at 10:22:47AM +, Mads N. Vestergaard wrote:
I have a script where I need to replace 45 in the beginning, with nothing
in a variable
It looks like this:
#!/usr/bin/perl
$modtager = "45247";
$modtager =~s/45//;
Then $modtager is 247, but if forinstance the
On Fri, Dec 02, 2005 at 10:22:47AM +, Mads N. Vestergaard wrote:
> I have a script where I need to replace 45 in the beginning, with nothing
> in a variable
>
> It looks like this:
>
> #!/usr/bin/perl
>
> $modtager = "45247";
>
> $modtager =~s/45//;
>
> Then $modtager is 247, but i
Hi Everybody,
I have a script where I need to replace 45 in the beginning, with nothing in a
variable
It looks like this:
#!/usr/bin/perl
$modtager = "45247";
$modtager =~s/45//;
Then $modtager is 247, but if forinstance the number is 4545247, it should
return 45247, how do I do this
