On Mon, 5 Nov 2001, Martin Karlsson wrote:
> Thanks a lot for your help and your time! I think I've got it solved
> now.
You're welcome. :>
> Could any of you recommend a good book for (learning) Perl? There seems
> to be quite a few to choose from...
Oddly enough, that's w
At 11:38 AM 11/4/01 -0800, Wagner-David wrote:
> If you only want to place parens around the input, then you can
> just place it parans like:
> $ARGV[0] = '(' . $ARGV[0] . ')';
Somewhat clearer:
$ARGV[0] = "($ARGV[0])";
> In your original code, you want
Martin,
I'm not entirely clear on what you're trying to do here, so if
this doesn't help, let me know and I'll try again.
I think the problem is that you're doing this:
s/$ARGV[0]/\($ARGV[0]\)/g
...when you want to affect $ARGV[0]. But remember that s/// and
m// are, b
Hi! Thanks for your help, I really appreciate it. However, I just don't
seem able to figure out how to do it; please have a look at the attached
script. Perhaps you can find some stupid rookie-mistake in it which
could explain why it's not working the way I want :-).
Have a nice week,
/Martin
* W
If you only want to place parens around the input, then you can just place it
parans like:
$ARGV[0] = '(' . $ARGV[0] . ')';
In your original code, you want to work with $ARGV[0] but the regex w/o inputs
assumes:
$_ =~ s/$ARGV[0]/\($ARGV[0]\)/g;
