John W. Krahn wrote:
} elsif ( $ARGV[0] =~
m/\b2008(0[1-9]|1[12])(0[1-9]|1[0-9]|2[0-9]|3[01])([01][0-9]|2[0-3])\b/
) {
^
So you don't want to test for October?
John
fixed now. thanks!!
} elsif ( $ARGV[0] =~
m/\b2008(0[1-9]|1[012])(0[1-9]|1[0-9]|2[0-9]|3[01])([01][
Richard Lee wrote:
John W. Krahn wrote:
Richard Lee wrote:
given then ARGV[0] is 2008052803, why woulnd't below regex match them??
2008052803 is a ten digit number.
} elsif ( $ARGV[0] =~ m/\b2008[01][1-31]([01][0-9]|2[0-3])\b/ ) {
Your pattern matches eight digits with a \b word boundary
John W. Krahn wrote:
Richard Lee wrote:
given then ARGV[0] is 2008052803, why woulnd't below regex match them??
2008052803 is a ten digit number.
} elsif ( $ARGV[0] =~ m/\b2008[01][1-31]([01][0-9]|2[0-3])\b/ ) {
Your pattern matches eight digits with a \b word boundary at each end
so it
John W. Krahn wrote:
Richard Lee wrote:
@array = qx#ls -tr $directory/$ARGV[0]*#;
Why not do that directly in perl:
@array = map $_->[0], sort { $a->[1] <=> $b->[1] } map [ $_, -M ],
glob "$directory/$ARGV[0]*";
Sorry, that should be:
@array = map $_->[0], sort { $b->[1] <
Richard Lee wrote:
given then ARGV[0] is 2008052803, why woulnd't below regex match them??
2008052803 is a ten digit number.
} elsif ( $ARGV[0] =~ m/\b2008[01][1-31]([01][0-9]|2[0-3])\b/ ) {
Your pattern matches eight digits with a \b word boundary at each end so
it will never match a ten
