Thanks!
-Original Message-
From: Dr.Ruud [mailto:[EMAIL PROTECTED]
Sent: Monday, August 28, 2006 12:00 PM
To: beginners@perl.org
Subject: Re: number rounding problem
Howard, Chris schreef:
[next time, do not toppost, and quote more effectively]
> Ruud:
>> Chris:
>&g
Howard, Chris schreef:
[next time, do not toppost, and quote more effectively]
> Ruud:
>> Chris:
>>> What starts out as 64.63 ends up being 0006462
>>
>> No, it ends up beint printed as that. Replace your %12.12d by one of
>> (%s, %f, %g) to get different representations.
>
> But the file o
OTECTED]
Sent: Monday, August 28, 2006 7:29 PM
To: Dr.Ruud; beginners@perl.org
Subject: RE: number rounding problem
But the file output format I'm required to produce is 12 positions with
leading zeros and no decimal.
:-(
Chris
-Original Message-
From: Dr.Ruud [mailto:[EMAIL PROTECTE
But the file output format I'm required to produce
is 12 positions with leading zeros and no decimal.
:-(
Chris
-Original Message-
From: Dr.Ruud [mailto:[EMAIL PROTECTED]
Sent: Monday, August 28, 2006 11:17 AM
To: beginners@perl.org
Subject: Re: number rounding problem
&q
"Howard, Chris" schreef:
> What starts out as 64.63 ends up being 0006462
No, it ends up beint printed as that. Replace your %12.12d by one of
(%s, %f, %g) to get different representations.
See also
perldoc -q decimals
--
Affijn, Ruud
"Gewoon is een tijger."
--
To unsubscribe, e-
Chris,
printf "credit %s, amount %12.12d\n", $credit, $amount;
What really went wrong was to use a %d specifier. It says to truncate
a floating number into integer. Like it happens in
$ perl -e 'print int 1000*shift' 64.63
64629
If you use %f, it may improve
$ perl -e 'printf "%f", 1000*s
