On Mon, Apr 13, 2009 at 04:49, Michael Alipio wrote:
snip
> my $pid = fork ();
You must check to see if $pid is defined. If it isn't
then fork failed. The parentheses are oddly placed and
unnecessary.
> if ($pid == 0){
> exec ("top");
Again with the odd parentheses placement. Function
calls
Hi,
I'm trying to launch and external program using fork.
my $pid = fork()
if ($pid == 0){
system ("top");
exit (0);
}else{
waitpid ($pid, 0)
}
print "External Program died!";
The problem is "top", or the program i'm actually going to run always detaches
to the child perl process I have
