Re: Use of uninitialized value in concatenation (.) or string at txt.pl line 33, line 11

2005-09-12 Thread Jeff 'japhy' Pinyan
On Sep 12, ganesh said: This is the warning messge I am getting when I executed my script. Please find my analysis of the above warning Input: Line 1: 20(1): 125-126 Line 2: 20:125-126 Output: Line 1: 20(1): 125-126 Line 2: 20:125-126 My Code: $line=~s!(\d+)(\(\d+\))?:(\d+)-!$1$2:$3-!

Re: Use of uninitialized value in concatenation (.) or string at...

2003-09-08 Thread Bernard Kenik
use what the message states; you are using an uninitialize string. example my $string;# $string is declared but not initialized! so any operation you do on that string (except an assignment) with produce the error message. - Original Message - From: "Devon Young" <[EMAIL PROTECTED

Re: Use of uninitialized value in concatenation (.) or string at...

2003-09-07 Thread R. Joseph Newton
Please do not cross-post. I know already that I am going to be burned with at least two failure notices by responding to your post before checking for rudeness. Since I am not subscribed to either of the other lists you *spammed*, my replies will be returned with either failure or "Awaiting ap

Re: Use of uninitialized value in concatenation (.) or string at...

2003-09-07 Thread R. Joseph Newton
Devon Young wrote: > What does this mean?? I'm thoroughly puzzled and I've been scouring the net > for an answer. I've been assuming it means I'm not putting strings together > correctly, but I can't figure out how to fix it. Here's the errors I'm > getting, followed by the peice of code that the

Re: Use of uninitialized value in concatenation (.) or string at...

2003-09-07 Thread Carl Jolley
On Sat, 6 Sep 2003, Devon Young wrote: > What does this mean?? I'm thoroughly puzzled and I've been scouring the net > for an answer. I've been assuming it means I'm not putting strings together > correctly, but I can't figure out how to fix it. Here's the errors I'm > getting, followed by the pei

RE: Use of uninitialized value in concatenation (.) or string at mlknpvs.pm line 241

2001-09-04 Thread Rob Dixon
Hi John I think you need to tell us something more. You say you my @parts = ("one", "two", "three"); substr($parts[1],0,0) = "."; print "@parts"; works fine. (Unless you really /did/ miss the closing quote from 'three'?). May we see a little more of your code? Don't forget that, i