One additional note:
The input data, column one has values 1 to 365(6)
Thanks
J.
>>> "Gerald Wheeler" <[EMAIL PROTECTED]> 11/26/2007 9:40 AM >>>
I am getting and error: Day '32" out of range 1..31 at ... line 35
for this line: my ( $d, $m, $y ) = ( localtime timelocal 0, 0, 12,
$_, 0, $dyr )
I am getting and error: Day '32" out of range 1..31 at ... line 35
for this line: my ( $d, $m, $y ) = ( localtime timelocal 0, 0, 12,
$_, 0, $dyr )[ 3, 4, 5 ];
and I don't quite know why.. The value for "$_" should be reset to 1
after Jan 31st..
Output is created through only January 31
Thank
Thanks I'll try in..
J.
>>> John W.Krahn <[EMAIL PROTECTED]> 11/21/07 9:26 PM >>>
On Wednesday 21 November 2007 09:40, Gerald Wheeler wrote:
> John,
> I have modified my script as per your suggestions:
>
>
> #!/usr/bin/perl
>
> use strict;
> use warnings;
>
> my $ifiln = 'abc.csv';
> my $ofiln = '
On Wednesday 21 November 2007 09:40, Gerald Wheeler wrote:
> John,
> I have modified my script as per your suggestions:
>
>
> #!/usr/bin/perl
>
> use strict;
> use warnings;
>
> my $ifiln = 'abc.csv';
> my $ofiln = 'xyz.txt';
>
> # get start year () from command line
> my($rsvr, $rdt, $dyr) = @
Gerald Wheeler wrote:
Gunnar Hjalmarsson wrote:
use Time::Local;
sub nextday {
my ($y, $m, $d) = split /\//, shift;
my $t = timegm 0, 0, 0, $d, $m-1, $y;
($d, $m, $y) = ( gmtime($t+24*60*60) )[3..5];
sprintf '%d/%02d/%02d', $y+1900, $m+1, $d;
}
On 11/21/07, Gerald Wheeler <[EMAIL PROTECTED]> wrote:
> It appears that Date::Calc would do what I need only I do not have
> access to additional modules
You don't need to be the system administrator to install modules. See
the perlmodinstall manpage.
http://perldoc.perl.org/perlmodinstall.
I checked and find that I do have the Time::Local module installed
The problem is ... how do I increment the day from start to end of the
calendar year?
If i initially set nextday to: 2007/01/01 how do i easily increment
this?
It appears that Date::Calc would do what I need only I do not have
acces
Gunnar,
I checked and find that I do have the Time::Local module installed
The problem is ... how do I increment the day from start to end of the
calendar year?
If i initially set nextday to: 2007/01/01 how do i easily increment
this?
Thanks
>>> Gunnar Hjalmarsson <[EMAIL PROTECTED]> 11/20/2
John,
I have modified my script as per your suggestions:
**
++
chomp() returns the number of $/ values that were removed from its argument(s)
so that is not what you want to do here.
You should probably have chomped the data when you input it.
++
I am attempting to remove the newline character at
First off thanks for the assistance
See inline comments:
>>> John W.Krahn <[EMAIL PROTECTED]> 11/20/2007 4:31:01 PM >>>
On Tuesday 20 November 2007 14:00, Gerald Wheeler wrote:
> Running Perl 5.6.1 on Solaris 9 SPARC
> No (access to) modules available other than what comes with the
basic
> perl i
On 11/20/07, Eric Krause <[EMAIL PROTECTED]> wrote:
> I think he can't download modules.
I think he *thinks* he can't download modules.
Cheers!
--Tom Phoenix
Stonehenge Perl Training
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Tom Phoenix wrote:
On 11/20/07, Gerald Wheeler <[EMAIL PROTECTED]> wrote:
No (access to) modules available other than what comes with the basic
perl installation.
*** I do NOT know how to increment (and format as "2007/01/01") date so
that it crosses over for each new month and know when it is
On Tuesday 20 November 2007 14:00, Gerald Wheeler wrote:
> Running Perl 5.6.1 on Solaris 9 SPARC
> No (access to) modules available other than what comes with the basic
> perl installation.
>
> I have a file: ifiln.csv as such:
> Julian Day of the year, value
> 1,4144.34
> 2,4144.38
> 3,4144.38
[
On 11/20/07, Gerald Wheeler <[EMAIL PROTECTED]> wrote:
> Running Perl 5.6.1 on Solaris 9 SPARC
> No (access to) modules available other than what comes with the basic
> perl installation.
> *** I do NOT know how to increment (and format as "2007/01/01") date so
> that it crosses over for each new
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