Re: Capturing STDOUT of system launched process

2001-12-13 Thread Jon Molin
Hi, some alternative approaches would be: my $res = `$cmd`; # note that it's not "'" but "`" # $res only stdout, this will puke out stderr or my $res = `$cmd 2>&1`; # redirect stderr to stdout # $res is now both stderr and stdout or my $res = `$cmd 2>/dev/null`; # throw away stderr # $res

Re: Capturing STDOUT of system launched process

2001-12-13 Thread insomniak
Hi, You can always write STDERR and STDOUT to a temp file then read the contents of this file back in to your script. eg system (some_command 1>.stdout 2>.stder); STDOUT is written to .stdout STDERR is written to .stderr Theres is probably a better way than this but I find this the easiest.

Re: Capturing STDOUT of system launched process

2001-09-26 Thread smoot
> "Jeff 'japhy' Pinyan" <[EMAIL PROTECTED]> said: > Of course, all of these should have error-checking: > > $x = `...` or die "can't run ...: $!"; > > open OUTPUT, "... |" or die "can't run ...: $!"; Don't forget to check the close for errors. If the pipe fails for some reason close retur

Re: Capturing STDOUT of system launched process

2001-09-26 Thread Jeff 'japhy' Pinyan
On Sep 27, Matthew Blacklow said: >What I need to do is capture the screen output of this process into a string >variable so that it can latter be manipulaterd. ie. capture the STDOUT. Several options: # qx() and `` are the same $output = `prog arg1 arg2`; $output = qx(prog arg1 arg2);