-Original Message-
From: Chas. Owens [mailto:chas.ow...@gmail.com]
Sent: Friday, May 29, 2009 10:22 AM
To: sanket vaidya
Cc: beginners@perl.org
Subject: Re: Range Operator Question
On Thu, May 28, 2009 at 23:49, sanket vaidya
wrote:
snip
> Can anyone write few simple codes explain
On Thu, May 28, 2009 at 23:49, sanket vaidya wrote:
snip
> Can anyone write few simple codes explaining the behavior that Chas
> mentioned, So that I can explore the codes for getting better picture?
snip
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
my @a = 1 ... 10;
print "norm
-Original Message-
From: sanket vaidya [mailto:sanket.vai...@patni.com]
Sent: Friday, May 29, 2009 9:20 AM
To: 'beginners@perl.org'
Subject: RE: Range Operator Question
-Original Message-
From: Chas. Owens [mailto:chas.ow...@gmail.com]
Sent: Thursday, May 28, 2009
-Original Message-
From: Chas. Owens [mailto:chas.ow...@gmail.com]
Sent: Thursday, May 28, 2009 5:55 PM
To: sanket vaidya
Cc: beginners@perl.org
Subject: Re: Range Operator Question
On Thu, May 28, 2009 at 07:51, sanket vaidya
wrote:
> Hi,
>
> I came across this statement abo
On Thu, May 28, 2009 at 07:51, sanket vaidya wrote:
> Hi,
>
> I came across this statement about 'range' operators somewhere.
>
> There is very little difference between $x..$y and $x...$y, and if the
> second operand is a constant then they are identical.
>
> What is the difference? Kindly explai
Hi,
I came across this statement about 'range' operators somewhere.
There is very little difference between $x..$y and $x...$y, and if the
second operand is a constant then they are identical.
What is the difference? Kindly explain with example.
Thanks & Regards,
Sanket Vaidya
