Thanks a lot Simon
-Frank
On Wed, Mar 25, 2015 at 5:44 PM, Simon Reinhardt
wrote:
> Hi Frank,
>
> when first learning regexps I read the section "In the World of Regular
> Expressions" in the Lama-Book [1]. If you find this introduction to
> slow, you might also take a look at chromatic's Moder
On Wed, 25 Mar 2015 10:31:40 +0530
Frank Vino wrote:
> Hi Team,
>
> How to understand Regular Expression in a easy way?
>
> Thanks,
> Frank
Sorry Frank but there's no easy way. ☹
Some things to remember:
Some punctuation marks have special meaning, like periods, question
marks, and asterisks
Hi Frank,
when first learning regexps I read the section "In the World of Regular
Expressions" in the Lama-Book [1]. If you find this introduction to
slow, you might also take a look at chromatic's Modern Perl, which is
available for free [2].
Regards, Simon
Am 25
Hi Frank,
On Wed, 25 Mar 2015 10:31:40 +0530
Frank Vino wrote:
> Hi Team,
>
> How to understand Regular Expression in a easy way?
>
This page has links to some recommended tutorials about learning regular
expressions:
http://perl-begin.org/topics/regular-expressions/
*NOTE*: I originated pe
Frank,
Just go through below site, it helps to build regex and test same easily.
http://www.regexr.com/
~Rahul
On Wed, Mar 25, 2015 at 10:42 AM, Akshay Mohit
wrote:
> Just start using it and you will find it very easy to understand.
>
> -Akshay
>
> On Wed, Mar 25, 2015 at 10:31 AM, Frank Vino
Just start using it and you will find it very easy to understand.
-Akshay
On Wed, Mar 25, 2015 at 10:31 AM, Frank Vino wrote:
> Hi Team,
>
> How to understand Regular Expression in a easy way?
>
> Thanks,
> Frank
>
---Original Message---
From: Jing Yu
To: Viet-Duc Le
Sent date: 2014-09-17 12:20:29 GMT +0900 (Asia/Seoul)
Subject: Re: Regular expression: option match after a greedy/non-greedy match
Hi Viet-Duc Le,
On 17 Sep 2014, at 10:23, Viet-Duc Le wrote:
Greeting from S
when i change
use 5.16.0; to use feature ':5.10';
it works i get following output
bash-4.2$ ./regex.pl
Use of uninitialized value $3 in say at ./regex.pl line 7, line 1.
Use of uninitialized value $4 in say at ./regex.pl line 7, line 1.
Video1280x720
Use of uninitialized value $2 in say at ./re
On 17 Sep 2014, at 17:08, Uday Vernekar wrote:
> When i run this script i get following Error
>
> bash-4.2$ ./regex.pl
> feature version v5.16.0 required--this is only version v1.160.0 at ./regex.pl
> line 4.
> BEGIN failed--compilation aborted at ./regex.pl line 4.
>
>
>
> But I am using p
When i run this script i get following Error
bash-4.2$ ./regex.pl
feature version v5.16.0 required--this is only version v1.160.0 at ./
regex.pl line 4.
BEGIN failed--compilation aborted at ./regex.pl line 4.
But I am using perl version as swon below.
bash-4.2$ perl -v
This is perl 5, version
Hi Viet-Duc Le,
On 17 Sep 2014, at 10:23, Viet-Duc Le wrote:
> Greeting from S. Korea !
>
> I am parsing the output of ffmpeg with perl. Particular, I want to print only
> these lines among the output and capturing the resolution, i.e. 1280x720.
>
> Stream #0:0: Video: h264 (High), yuv42
gt; From: u...@stemsystems.com
> To: beginners@perl.org
> Subject: Re: regular expression
>
> On 05/07/2014 01:40 AM, John SJ Anderson wrote:
>
> >
> > my @strings = (
> >"^Modifications made by Danny Wong (danwong) on 2014/05/06 18:27:48
> > from da
On 05/07/2014 01:40 AM, John SJ Anderson wrote:
my @strings = (
"^Modifications made by Danny Wong (danwong) on 2014/05/06 18:27:48
from database brms" ,
"^Modifications made by danwong on 2014/05/06 18:27:48 from database brms²",
);
foreach my $string ( @strings ) {
my( $match ) = $s
On Tue, May 6, 2014 at 10:30 PM, Danny Wong (dannwong)
wrote:
> Both string are possible outputs, so I want to be able to grep for the
> username only.
Well, if the username will always be either the only thing between
'by' and 'on', or in parens if it's not...
#! /usr/bin/env perl
use strict;
On Wed, May 7, 2014 at 1:19 AM, Danny Wong (dannwong)
wrote:
> Hi Guys,
> I have the following strings.
>
> my $str1="^Modifications made by Danny Wong (danwong) on 2014/05/06
> 18:27:48 from database brms";
>
> #$str1="^Modifications made by danwong on 2014/05/06 18:27:48 from
> database
Both string are possible outputs, so I want to be able to grep for the
username only.
I tried this, but it works for the string without parentheses.
"^Modifications made by danwong on 2014/05/06 18:27:48 from database brms",
$str1 =~ /by.*?[(]?(.*?)[)]?\s+on/i;
The one with partheses gives me
On Tue, May 6, 2014 at 10:19 PM, Danny Wong (dannwong)
wrote:
> What is a regular expression where I can extract ³danwong² from either
> string (one string have () parentheses and the other doesn¹t have
> parentheses)?
I'm not entirely sure what you're trying to accomplish, but perhaps
something
Chaps,
I am testing all your code one by one, Appreciate your time and detailed
inputs.
Many Thanks
Sj
On Fri, Aug 23, 2013 at 6:01 PM, Jim Gibson wrote:
>
> On Aug 23, 2013, at 9:06 AM, jet speed wrote:
>
> > Chaps,
> >
> > Please i need help on the regular expression, i have the sample cod
On Aug 23, 2013, at 9:06 AM, jet speed wrote:
> Chaps,
>
> Please i need help on the regular expression, i have the sample code below.
> I only want to match the entries from the array to the file and print the
> matching line
>
> for example if i only want to match fc3/23, in my code it print
See sample code below
> Chaps,
>
> Please i need help on the regular expression, i have the sample code
> below.
> I only want to match the entries from the array to the file and print
> the
> matching line
>
> for example if i only want to match fc3/23, in my code it prints both
> the
> lines f
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed wrote:
> Chaps,
>
> Please i need help on the regular expression, i have the sample code
> below. I only want to match the entries from the array to the file
> and print the matching line
>
> for example if i only want to match fc3/23, in my code it
On Fri, 23 Aug 2013 17:06:41 +0100
jet speed wrote:
> my @check = (fc3/23, fc10/1, fc3/14, fc12/12);
my @check = qw( fc3/23 fc10/1 fc3/14 fc12/12 );
>
> my $f2 = 'out.txt';
> for my $element(@check) {
> open my $fh2, '<', $f2 or die "could not open $f2: $!";
> while (my $line = <$fh2>) {
> cho
Not sure I get it, but would
/^fc3\/2\b/
(assuming you're looking for fc3/2 and not fc3/23) work?
hth
paolino
On 23 Aug 2013, at 17:06, jet speed wrote:
> Chaps,
>
> Please i need help on the regular expression, i have the sample code below.
> I only want to match the entries from the array
From: "Dr.Ruud"
On 2012-09-20 09:08, Octavian Rasnita wrote:
my ( $file_name ) = $data =~ /([^\\]+)$/g;
No need for that g-modifier.
--
Ruud
Yes, you are right. I added it by mistake.
Octavian
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail:
On 2012-09-20 09:08, Octavian Rasnita wrote:
my ( $file_name ) = $data =~ /([^\\]+)$/g;
No need for that g-modifier.
--
Ruud
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
thanks a lot for all the responses :)
regards
From: Shlomi Fish
To: Michael Brader
Cc: beginners@perl.org
Sent: Thursday, September 20, 2012 2:53 PM
Subject: Re: regular expression help
On Thu, 20 Sep 2012 17:13:07 +0930
Michael Brader wrote:
> A m
On Thu, 20 Sep 2012 17:13:07 +0930
Michael Brader wrote:
> A more idiomatic way to do this is to use the File::Spec module.
> Inspect the output of this program for inspiration:
>
There's also File::Basename:
http://perldoc.perl.org/File/Basename.html
Regards,
Shlomi Fish
--
--
On 09/20/2012 04:39 PM, Irfan Sayed wrote:
got it myself :)
thanks a lot
$line_to_add =~ m/([a-zA-Z]+\.csproj)/;
Hi Irfan,
Your solution will only match files that consist of ASCII alphabetic
characters followed by '.csproj'. It will also match these:
* 'c:\p4\car\abc\foo.csproj\file.tx
got it myself :)
thanks a lot
$line_to_add =~ m/([a-zA-Z]+\.csproj)/;
regards
From: Irfan Sayed
To: Perl Beginners
Sent: Thursday, September 20, 2012 12:07 PM
Subject: regular expression help
i have string 'c:\p4\car\abc\xyz.csproj'
i just need to matc
From: "Irfan Sayed"
i have string 'c:\p4\car\abc\xyz.csproj'
i just need to match the xyz.csproj
i tried few option but does not help.
can someone please suggest
regards
irfan
my $data = 'c:\p4\car\abc\xyz.csproj';
my ( $file_name ) = $data =~ /([^\\]+)$/g;
print $file_name;
It will p
On 15/07/2011 16:42, David Wagner wrote:
I have the following map:
map{[$_,(/^\d/ ? 1 : 0) . /^([^;]+)/,
/[^;]+;[^;]*;[^;]+;[^;]+;([^;]+);/]}
I had a failure during the night because some data field(s) had
a semi-colon in the data. So what I have is a
On 2011-07-15 17:42, Wagner, David --- Sr Programmer Analyst --- CFS wrote:
I have the following map:
map{[$_,(/^\d/ ? 1 : 0) . /^([^;]+)/,
/[^;]+;[^;]*;[^;]+;[^;]+;([^;]+);/]}
I had a failure during the night because some data field(s) had
a semi-colon
Hi All,
Thanks for your time and valuable inputs, Appreciate it.
I will try your suggestions and test it in my program.
Sj
On May 11, 8:38 am, speedj...@googlemail.com (jet speed) wrote:
> Hi All,
>
> I need help in matching the regular expression, the file is as below.
>
> I am trying to match number followed by Number ex 587, 128 in $1 and
> 60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
>
> the $1 match works
On 11/05/2011 16:38, jet speed wrote:
> Hi All,
>
> I need help in matching the regular expression, the file is as below.
>
> I am trying to match number followed by Number ex 587, 128 in $1 and
> 60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
>
> the $1 match works find with regulare exp
On 11-05-11 11:38 AM, jet speed wrote:
I need help in matching the regular expression, the file is as below.
I am trying to match number followed by Number ex 587, 128 in $1 and
60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11 in $2
the $1 match works find with regulare expression #if ($_=~
/\w
I ended up confused after reading your email.
Please specify INPUT + OUTPUT/condition.
You have already specify INPUT which is:
LOGICAL UNIT NUMBER 587
UID:60:06:01:60:42:40:21:00:3A:AA:55:37:91:8A:DF:11
LOGICAL UNIT NUMBER 128
UID:60:06:01:60:50:4
> "KK" == Karl Kaufman writes:
KK> Well, to be precise, your conceptual logic was fine; the
KK> implementation was flawed. As several have pointed out, you
KK> weren't replacing the comma with a _space_ *character*, but with
KK> the RegExp _whitespace_ *character class*.
to be really
- Original Message -
From: "Irfan Sayed"
To: "John W. Krahn" ; "Perl Beginners"
Sent: Thursday, April 28, 2011 9:28 AM
Subject: Re: regular expression
my logic was to just put the space character in place of comma and keep
rest as it is
but un
thanks all
From: Shawn H Corey
To: beginners@perl.org
Sent: Thursday, April 28, 2011 7:55 PM
Subject: Re: regular expression
On 11-04-28 10:05 AM, Irfan Sayed wrote:
> hi,
>
> i have following code.
>
>
> $target = "abc,xyz";
&g
: Re: regular expression
Irfan Sayed wrote:
> hi,
Hello,
> i have following code.
>
>
> $target = "abc,xyz";
> print "$target\n";
> $target =~ s/,/\s/g;
> print "$target\n";
>
> i need to replace "comma" with whitespace for st
On 11-04-28 10:05 AM, Irfan Sayed wrote:
hi,
i have following code.
$target = "abc,xyz";
print "$target\n";
$target =~ s/,/\s/g;
print "$target\n";
i need to replace "comma" with whitespace for string "abc,xyz"
the output shud be "abc xyz"
the above regular expression does not do that . pl
John W. Krahn wrote:
Irfan Sayed wrote:
i have following code.
$target = "abc,xyz";
print "$target\n";
$target =~ s/,/\s/g;
print "$target\n";
i need to replace "comma" with whitespace for string "abc,xyz"
"Whitespace" is something that applies only to regular expressions but
the second pa
Irfan Sayed wrote:
hi,
Hello,
i have following code.
$target = "abc,xyz";
print "$target\n";
$target =~ s/,/\s/g;
print "$target\n";
i need to replace "comma" with whitespace for string "abc,xyz"
"Whitespace" is something that applies only to regular expressions but
the second part of
Excellent Guys, I would like thank each one of you for inputs. Much
appreciated.
i got blinded by just the numbers 0079, i didn't cater for the next line
which is hex 007A, as one of you rightly pointed out [ 0-9A-Z] , does the
trick. its amazing to see different technique to achieve the same res
On 2011-04-27 18:47, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9],
Beware: the \d matches 250+ code points. So don't use \d if you only
mean [0-9].
not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
Or us
On Wed, Apr 27, 2011 at 2:48 PM, Shawn H Corey wrote:
> On 11-04-27 12:47 PM, Jim Gibson wrote:
>
>> The metasymbol \d matches the characters [0-9], not the extended
>> hexadecimal
>> set that includes A-Z. To match those, construct your own character class:
>>
>> [0-9A-Z]
>>
>
> You can use the
On 11-04-27 12:47 PM, Jim Gibson wrote:
The metasymbol \d matches the characters [0-9], not the extended hexadecimal
set that includes A-Z. To match those, construct your own character class:
[0-9A-Z]
You can use the POSIX xdigit character class instead:
#!/usr/bin/env perl
use strict;
use w
On Wed, Apr 27, 2011 at 04:32:57PM +0100, jet speed wrote:
> Hi all,
>
> Thanks for all our inputs,
>
> The regular expression below works fine if do it for single line, i am
> trying to caputre the match $1, and $2 into array. only the first line
> is pushed to the array. what am i doing wrong ?
On 4/27/11 Wed Apr 27, 2011 8:32 AM, "jet speed"
scribbled:
> Hi all,
>
> Thanks for all our inputs,
>
> The regular expression below works fine if do it for single line, i am
> trying to caputre the match $1, and $2 into array. only the first line
> is pushed to the array. what am i doing wr
Hi all,
Thanks for all our inputs,
The regular expression below works fine if do it for single line, i am
trying to caputre the match $1, and $2 into array. only the first line
is pushed to the array. what am i doing wrong ?
how to get all the $1 and $2 match values for each line into arrary ?
Ki
On 27/04/2011 11:47, jet speed wrote:
Please could you advice, how can i write a regular expression for the
line below to capture 0079 and 69729260057253303030373
0079 Not Visible 69729260057253303030373
i tried this one, no luck
/(^\d{4})\s\w+\s\w+\s+\d+/ig)
It
2011/4/27 jet speed :
> Hi,
>
> Please could you advice, how can i write a regular expression for the
> line below to capture 0079 and 69729260057253303030373
>
>
> 0079 Not Visible 69729260057253303030373
>
This might help?
$ perl -le '
$str="0079 Not Visible
On 11-04-27 06:47 AM, jet speed wrote:
0079 Not Visible 69729260057253303030373
Try this:
#!/usr/bin/env perl
use strict;
use warnings;
my $text = '0079 Not Visible 69729260057253303030373';
my @numbers = $text =~ /(\d+)/g;
print "@numbers\n";
__END_
2011/4/27 jet speed
> Hi,
>
> Please could you advice, how can i write a regular expression for the
> line below to capture 0079 and 69729260057253303030373
>
>
> 0079 Not Visible 69729260057253303030373
>
> i tried this one, no luck
>
> /(^\d{4})\s\w+\s\w+\s+\d+/ig)
>
I agree completely with you, clean code is the best documentation.
But in your snippet I have to say: The use of $& anywhere in a program
imposes a considerable performance penalty on all regular expression
matches.
it would be better to avoid default/magic variables. I would consider
this snippe
At 13:39 +0300 12/04/2011, Shlomit Afgin wrote:
I need to write regular expression that will capitalize the first
letter of each word in the string.
Word should be word that her length is greater or equal to 3 letters
exclude the words 'and' and 'the'.
I tried:
$string = lc($string);
$string
On 13/04/2011 07:10, Shlomit Afgin wrote:
>
> I need to write regular expression that will capitalize the first letter of
> each word in the string.
> Word should be string with length that is greater or equal to 3 letters
> exclude the words 'and' and 'the'.
>
>
> I tried:
> $string = lc($st
On Apr 12, 11:10 pm, shlomit.af...@weizmann.ac.il ("Shlomit Afgin")
wrote:
> Hi
>
> I need to write regular expression that will capitalize the first letter of
> each word in the string.
> Word should be string with length that is greater or equal to 3 letters
> exclude the words 'and' and '
Hi Ramprasad,
thanks for your answer, but see below for my comments.
On Wednesday 13 Apr 2011 14:30:36 Ramprasad Prasad wrote:
> On 13 April 2011 11:40, Shlomit Afgin wrote:
> > Hi
> >
> >
> > I need to write regular expression that will capitalize the first letter
> > of each word in the stri
On 13 April 2011 11:40, Shlomit Afgin wrote:
>
>
>
>
> Hi
>
>
> I need to write regular expression that will capitalize the first letter of
> each word in the string.
> Word should be string with length that is greater or equal to 3 letters
> exclude the words 'and' and 'the'.
>
>
> I tried:
> $
Shlomit Afgin wrote:
Hi
Hello,
I need to write regular expression that will capitalize the first letter of
each word in the string.
Word should be string with length that is greater or equal to 3 letters
exclude the words 'and' and 'the'.
I tried:
$string = lc($string);
$string =~ s/\b(\
On 09/04/2011 21:30, Olof Johansson wrote:
On 2011-04-10 01:40 +0530, Sunita Rani Pradhan wrote:
You are right. Thanks for pointing out. Can you help me getting it
correct ?
Somebody already mentioned Regex::Common.
Use the same module for email addresses:
use Regexp::Common qw/ net Emai
On 2011-04-10 01:40 +0530, Sunita Rani Pradhan wrote:
> Hi Johan
s/Johan/Olof/, but who keeps score?
> You are right. Thanks for pointing out . Can you help me
> getting it correct ?
Somebody already mentioned Regex::Common.
--
- Olof Johansson
- www: http://www.stdlib.se/
-
Hi Johan
You are right. Thanks for pointing out . Can you help me
getting it correct ?
Thanks
Sunita
-Original Message-
From: Olof Johansson [mailto:o...@ethup.se]
Sent: Sunday, April 10, 2011 12:13 AM
To: beginners@perl.org
Subject: Re: regular expression for email id and IP
On 2011-04-09 23:53 +0530, Sunita Rani Pradhan wrote:
> Yes it is matching 167.249.0.0 .
But it's also matching things like "42". Feature?
Read about quantifiers, and also about the precedence of |.
--
- Olof Johansson
- www: http://www.stdlib.se/
- {mail,xmpp}: o...@ethup.se
- ir
use Regexp::Common qw/ net /;
$ip =~ /$RE{net}{IPv4}/;
Yes it is matching 167.249.0.0 .
-Sunita
-Original Message-
From: Jim Gibson [mailto:jimsgib...@gmail.com]
Sent: Saturday, April 09, 2011 11:50 PM
To: Perl Beginners
Subject: Re: regular expression for email id and IP address
At 11:42 PM +0530 4/9/11, Sunita Rani Pradhan wrote:
>Hi
At 11:42 PM +0530 4/9/11, Sunita Rani Pradhan wrote:
Hi All
1. Can anybody guide me to write a regular expression to
verify correct Email address ?
peldoc -q valid "How do I check a valid mail address?"
2. I have written a regular expression to verify correct
On 2011-03-06 17:22, Shlomit Afgin wrote:
I have a data that contain unseen characters that I want to delete.
The unseen characters can be ^L, ^N and other sign that I cannot copy but I
see them in my data.
Is someone know which regular can help me.
See perldoc perlre, specifically [:cntrl
On 06/03/2011 16:22, Shlomit Afgin wrote:
I have a data that contain unseen characters that I want to delete.
The unseen characters can be ^L, ^N and other sign that I cannot
copy but I see them in my data.
Is someone know which regular can help me.
Hi Shlomit.
It would be better to list th
>
> I have a data that contain unseen characters that I want to delete.
> The unseen characters can be ^L, ^N and other sign that I cannot copy but I
> see them in my data.
>
> Is someone know which regular can help me.
May you try the "dos2unix" command?
--
To unsubscribe, e-mail: beg
At 18:52 +0800 03/02/2011, Jeff Pang wrote:
2011/2/2 Shlomit Afgin :
> I tried to convert html special characters to their real character.
> For example, converting ” to " .
>
> I had the string
> $str = "“ test ” ÈÒÈÂÔ†¢ª
> The string contain also Hebrew letters.
Could E
On 11-02-02 04:25 AM, Shlomit Afgin wrote:
I tried to convert html special characters to their real character.
For example, converting” to " .
I had the string
$str = "“ test” ניסיון ";
The string contain also Hebrew letters.
This seems to work:
#!/usr/bin/perl
use strict;
use war
2011/2/2 Shlomit Afgin :
>
>
> Hello,
>
> I tried to convert html special characters to their real character.
> For example, converting ” to " .
>
> I had the string
> $str = "“ test ” ניסיון ";
> The string contain also Hebrew letters.
>
Could Encode work on it?
use Encode;
$new =
On Nov 2, 3:50 am, h...@risoe.dtu.dk ("Larsen, Henning Engelbrecht")
wrote:
> I want to search a string for patterns but starting the search from the
> _end_ instead of from the beginning, using a regular expression.
>
> For instance I want to find the last 'E' in the string
>
> ...looong string po
On Wednesday 03 Nov 2010, Uri Guttman wrote:
>
> try: 'E123EEExyz'
>
> your \b at the end also breaks many cases.
>
> perl -le 'print $1 if ("EE123EExyz" =~ /.*(E)\d*\b/)'
> perl -le 'print $1 if ("EE123abc" =~ /.*(E)\d*\b/)'
> perl -le 'print $1 if ("EE123EExyzE" =~ /.*(E)\d*\b/)'
> E
>
>
> "APK" == Akhthar Parvez K writes:
APK> Hi Uri,
APK> On Wednesday 03 Nov 2010, Uri Guttman wrote:
APK> $catch = $1 if ($string =~ /.*(E)\d*\b/);
>>
>> he didn't say there will be digits at the end. what if there aren't? his
>> example was just random text following the last E.
Hi Uri,
On Wednesday 03 Nov 2010, Uri Guttman wrote:
> APK> $catch = $1 if ($string =~ /.*(E)\d*\b/);
>
> he didn't say there will be digits at the end. what if there aren't? his
> example was just random text following the last E.
It will match even if there are no digits at the end:
input:
> "APK" == Akhthar Parvez K writes:
APK> Hi Henning,
APK> $catch = $1 if ($string =~ /.*(E)\d*\b/);
APK> you can use this to test it:
APK> $catch = $1 if ($string =~ /.*(E\d*)\b/);
he didn't say there will be digits at the end. what if there aren't? his
example was just random text
Hi Henning,
$catch = $1 if ($string =~ /.*(E)\d*\b/);
you can use this to test it:
$catch = $1 if ($string =~ /.*(E\d*)\b/);
--
Regards,
Akhthar Parvez K
http://www.sysadminguide.com/
UNIX is basically a simple operating system, but you have to be a genius to
understand the simplicity - Dennis
At 11:50 AM +0100 11/2/10, Larsen, Henning Engelbrecht wrote:
I want to search a string for patterns but starting the search from the
_end_ instead of from the beginning, using a regular expression.
Not a regular expression, but if all you are looking for is a
substring, use rindex:
perldoc
On Tue, Nov 2, 2010 at 5:50 AM, Larsen, Henning Engelbrecht <
h...@risoe.dtu.dk> wrote:
> I want to search a string for patterns but starting the search from the
> _end_ instead of from the beginning, using a regular expression.
>
>
Try something like this:
$string = "...looong string possibly wi
On Aug 14, 6:28 am, dery...@gmail.com ("C.DeRykus") wrote:
> On Aug 13, 1:47 pm, tobias.wage...@googlemail.com (irata) wrote:
>
>
>
>
>
> > I want to replace in a javscript structure like the one below every
> > occurence of "{#...}", "{?...}", "{+...}" and "{=...}" through
> > something different
On Aug 13, 1:47 pm, tobias.wage...@googlemail.com (irata) wrote:
>
> I want to replace in a javscript structure like the one below every
> occurence of "{#...}", "{?...}", "{+...}" and "{=...}" through
> something different (also nested):
> function() {
> test1 = "{#Caption}";
> tes
On 8/13/10 Fri Aug 13, 2010 1:47 PM, "irata"
scribbled:
> Hi...
>
> I want to replace in a javscript structure like the one below every
> occurence of "{#...}", "{?...}", "{+...}" and "{=...}" through
> something different (also nested):
Check out the Text::Balanced module, available at CPAN:
Thanks very much for clearing my doubts.
Regards,
Durai
On Tue, Mar 2, 2010 at 7:44 PM, Johann Markl
wrote:
> Hello
>
> Durairaj Muthusamy wrote:
>> I am a newbie and need your help. The following script doesn't
>> display the first print statement like the second one.
>> Why?
>
>> pri
Hello
Durairaj Muthusamy wrote:
> I am a newbie and need your help. The following script doesn't
> display the first print statement like the second one.
> Why?
> print "First: $&" if ?(foo.*)?;
> print "Second: $&" if /(foo.*)/;
The delimiters for the regular expressions behav
On Tue, Mar 2, 2010 at 5:45 PM, Durairaj Muthusamy wrote:
> Hi,
>
> I am a newbie and need your help. The following script doesn't
> display the first print statement like the second one.
> Why?
>
> @str = qw(NEW food foosball newstr foobasefoot);
>
> $\ = "\n";
>
> foreach(@str)
> {
>pr
On Wed, Aug 26, 2009 at 03:46, Dave Tang wrote:
snip
>> for my $token ($line =~ /([,"]|[^,"]+)/g) {
>
> I changed the single pipe (|) to double pipes (||) and $token also contained
> empty strings. Could you explain the difference between the pipes?
snip
The pipe character in regexes creates an al
On Wed, 26 Aug 2009 16:41:39 +1000, Chas. Owens
wrote:
On Wed, Aug 26, 2009 at 02:23, Dave Tang wrote:
Dear list,
I am trying to import entries in a csv file into a relational database,
however there are entries such as:
a,b,c,d,e,"f1,f2","g1,g2" which spoil my split(/,/).
snip
Sounds li
On Wed, Aug 26, 2009 at 02:23, Dave Tang wrote:
> Dear list,
>
> I am trying to import entries in a csv file into a relational database,
> however there are entries such as:
>
> a,b,c,d,e,"f1,f2","g1,g2" which spoil my split(/,/).
snip
Sounds like a job for [Text::CSV][1]. Of course, you an alway
> "DT" == Dave Tang writes:
DT> a,b,c,d,e,"f1,f2","g1,g2" which spoil my split(/,/).
DT> Could someone provide some guidance?
use a CSV module. parsing csv files is a pain with regexes (even if
doable). there are very stable and fast csv modules on cpan so get one
and use it.
uri
--
Irfan Sayed wrote:
Hi All,
Hello,
need help on regular expression.
i have string like this
"ProductName" = "8:EXFO RTU System 1.2.42"
now i want regular expression in such a way that it will change the line to :
"ProductName" = "8:EXFO RTU System 1.2.43"
$ perl -le'
$_ = q["ProductNa
it is not just 1.2.43 it may be anything
it may be like 2.3.56 or 2.0.12 and so on...
plz advice
From: Ajay Kumar
To: Irfan Sayed
Cc: "beginners@perl.org"
Sent: Wednesday, June 17, 2009 5:01:41 PM
Subject: RE: regular expression help
Hi Irfan
Hi Irfan
This code solve your problem
my $p="\"ProductName\" = \"8:EXFO RTU System 1.2.42\"";
my ($val)=$p=~ m/\d+.\d+.(\d+)\"/;
my $inval=$val+1;
$p=~s/$val/$inval/;
print"===$p\n";
thanks
Ajay
-Original Message-
From: Irfan Sayed [mailto:irfan_sayed2...@yahoo.com]
Sent: Wednesday, June
On Thu, Jan 8, 2009 at 23:25, howa wrote:
> Hello,
>
>
> Consider the string:
>
> $s = '[[2003]] abc [[2008]] "def"';
>
>
> I want to extract 2008 and def, so using
>
>
> \[\[([\w\W^\]]+?)\]\]\s"(.+?)"
>
> The regex match all string, even thought I have added to exclude: ^\]
> inside the character
On Thu, 2009-01-08 at 20:25 -0800, howa wrote:
> Hello,
>
>
> Consider the string:
>
> $s = '[[2003]] abc [[2008]] "def"';
>
>
> I want to extract 2008 and def, so using
>
>
> \[\[([\w\W^\]]+?)\]\]\s"(.+?)"
>
> The regex match all string, even thought I have added to exclude: ^\]
> inside t
Rob Coops wrote:
> On Tue, Nov 18, 2008 at 9:52 AM, howa <[EMAIL PROTECTED]> wrote:
>
>> Hello,
>>
>> I have two strings:
>>
>> 1. abc
>> 2. abc&
>>
>>
>> The line of string might end with "&" or not, so I use the expression:
>>
>> (.*)[$&]
>>
>> Why it didn't work out?
>
> This does not work bec
Hello
On Nov 18, 8:18 pm, [EMAIL PROTECTED] (Rob Coops) wrote:
> If you want to capture both lines you end up doing
> somehting like this: (.*)&{0,1}$
Thanks.
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