On 12/12/06, Helliwell, Kim <[EMAIL PROTECTED]> wrote:
I think you need to do:
my %loginhash = {};
That's not right. {} is a hash ref, not a hash. It stands for a scalar value.
When you do that
my %h = {}
or, for the same result,
my %h = 1;
my %h = "abacate";
you end with a hash
I think you need to do:
my %loginhash = {};
Kim Helliwell
LSI Logic Corporation
Work: 408 433 8475
Cell: 408 832 5365
[EMAIL PROTECTED]
Please Note: My email address changed to [EMAIL PROTECTED] on Oct
14. The old email address ([EMAIL PROTECTED]) will stop working after
Jan 15, 2007. Please up
On 12/12/06, Dukelow, Don <[EMAIL PROTECTED]> wrote:
I'm trying to declare a zero size hash so a sub function can populate it and
be see by all other sub's.
my %loginHash();
Maybe you mean this?
my %loginHash = ();
But every new variable (which is what 'my' is declaring) starts out
empty
On 12/12/06, Dukelow, Don <[EMAIL PROTECTED]> wrote:
I'm trying to declare a zero size hash so a sub function can populate it and
be see by all other sub's.
my %loginHash();
my %loginHash;
should be enough.
But the "use strict" doesn't like it.
It is not "use strict" that does not like i
Just write it like:
my %loginHash = ();
This should work.
-Original Message-
>From: "Dukelow, Don" <[EMAIL PROTECTED]>
>Sent: Dec 13, 2006 12:23 AM
>To: beginners@perl.org
>Subject: declaring a zero size hash
>
>I'm trying to declare a zero size hash so a sub function can populate it and
