On Tue, Jun 26, 2001 at 04:46:24PM -0400, Bradford Ritchie wrote:
> ...but I really need to print everything after the 8th element. If the
> ...array were named, I could do something like this:
>
> @arr = split(/:/);
> print @arr[1,6,8..$#arr]);
Your asked question was answered well by St
I don't think so. I do (split)[-1] regularly and it works fine. If you
left out the parens however it would think this was a pattern to match. I
was told by someone on perlmonks that the failure of [3 .. -1] with split is
something that should be fixed in subsequent versions of Perl.
>
> [
[1,6,8..-1]
in this case "-" is seen as a metacharacter inside the character class and
is not seen as -1
Hi,
I have an unnamed array which I created from splitting up a colon separated
string:
$_ = "0th:1st:2nd:3rd:4th:5th:6th:7th:Some random text: might have
:colons: or might n
Bradford wrote:
> Hi,
>
> I have an unnamed array which I created from
> splitting up a colon separated string:
>
> $_ = "0th:1st:2nd:3rd:4th:5th:6th:7th:Some
> random text: might have :colons: or might not"
> print ((split /:/)[1,6,8]);
>
> ...but I really need to print everythi
Well, if you're OK with printing the colons in the last field, you could
simply say:
print ( ( split(/:/, $_, 9) )[1,6,8] );
Since that'll absorb all of the ending fields into the ninth (from zero, so
index 8) field. That would be the correct thing to do if the colons in the
ending field are not
