This could be it. My final question is how to do it when we have two
arrays to pass to a subroutine. I am using the techniques I came
accross in perldoc perlsub but could not figure out what should I have
on the marked line.
sub func2 {
my ($local_value, $local_array) = @_;
foreach my $v
Khairul Azmi wrote:
Thanks for the solution. Not sure if this is still on topic but I then
add an additional parameter to the subroutine
sib func {
my (@local_array, $local_value) = @_;
print "$local_value \n";
for my $array ( @local_array ) {
for my $element ( @$array ) {
pri
Thanks for the solution. Not sure if this is still on topic but I then
add an additional parameter to the subroutine
sib func {
my (@local_array, $local_value) = @_;
print "$local_value \n";
for my $array ( @local_array ) {
for my $element ( @$array ) {
print "$element ";
On Thu, 2004-10-28 at 10:19, Khairul Azmi wrote:
> I've been trying to solve this problem using many techniques I found
> on the websites but still unsuccessfully
Hi.
I don't have much time, so I probably won't be able to explain this
right now, but here's a working version of your code, give it
Khairul Azmi wrote:
I've been trying to solve this problem using many techniques I found
on the websites but still unsuccessfully
sub func {
my (@local_array) = @_;
for (my $i=0;$i<@local_array;$i++) {
for (my $j=0;$j<@local_array[$i];$j++) {
print "$local_array[$i[[$j] ";
>I've been trying to solve this problem using many techniques I found
>on the websites but still unsuccessfully
>
>sub func {
> my (@local_array) = @_;
>
> for (my $i=0;$i<@local_array;$i++) {
> for (my $j=0;$j<@local_array[$i];$j++) {
> print "$local_array[$i[[$j] ";
> }
>
