ill do not get the reason for it.
>>Could someone shed a light on this precedence confusion?
>
>If we remove some parentheses:
>
>my $server = ( shift || ( $string =~ /(foo|bar)/ ) ) ? $1 :
>'default';
>
Aha! Now I get it.
>
>Or you could just read perlop:
&g
| ($string =~ /(foo|bar)/ ? $1 : 'default');
While this solves my problem, I still do not get the reason for it.
Could someone shed a light on this precedence confusion?
You can ask perl to do it for you:
$ perl -MO=Deparse,-p -e'sub sitemode { my $server = shift || $string =~
/(foo|bar)
n for it. Could
someone shed a light on this precedence confusion?
Thanks,
Jan
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