Ricardo SIGNES wrote:
* "Randal L. Schwartz" [2006-11-14T16:34:43]
"Rob" == Rob Dixon <[EMAIL PROTECTED]> writes:
This is indeed a documentation bug. perlop says, in full:
~ The "=>" operator is a synonym for the comma, but forces any word
~ (consisting entirely of word characters) to its
Randal L. Schwartz schreef:
> Ruud:
>>
>> The "=>" operator is a synonym for the comma, but forces any
>> word to its left to be interpreted as a string (as of 5.001).
>>
>>
>> And AFAICS that isn't true:
>>
>> $ perl -MData::Dumper -wle'
>> %n = (00 => Integer, 01 => Floating, 10 => Char, 11
* "Randal L. Schwartz" [2006-11-14T16:34:43]
> > "Rob" == Rob Dixon <[EMAIL PROTECTED]> writes:
>
> Rob> This is indeed a documentation bug. perlop says, in full:
> Rob> ~ The "=>" operator is a synonym for the comma, but forces any word
> (consisting
> Rob> ~ entirely of word characters) to
> "Rob" == Rob Dixon <[EMAIL PROTECTED]> writes:
Rob> This is indeed a documentation bug. perlop says, in full:
Rob> ~ The "=>" operator is a synonym for the comma, but forces any word
(consisting
Rob> ~ entirely of word characters) to its left to be interpreted as a string
(as of
Rob> ~ 5.
Randal L. Schwartz wrote:
>
> ""Dr" == Ruud" writes:
>>
>>
>> The "=>" operator is a synonym for the comma, but forces any word to
>> its left to be interpreted as a string (as of 5.001).
>>
>>
>> And AFAICS that isn't true:
>>
>> $ perl -MData::Dumper -wle'
>> %n = (00 => Integer, 01 => Floa
> ""Dr" == "Dr Ruud" writes:
"Dr>
"Dr> The "=>" operator is a synonym for the comma, but forces any word to
"Dr> its left to be interpreted as a string (as of 5.001).
"Dr>
"Dr> And AFAICS that isn't true:
"Dr> $ perl -MData::Dumper -wle'
"Dr> %n = (00 => Integer, 01 => Floating, 10 => C
"John W. Krahn" schreef:
> Dharshana Eswaran:
>> %TypeofNumber = ( 00 => Integer, 01 => Floating, 10 => Char, 11 =>
>> Double );
>
> Perl interprets numbers beginning with 0 as octal and the other
> numbers as decimal so 00 is the number 0, 01 is the number 1, 10 is
> the number ten and 11 is th
Dharshana Eswaran wrote:
> Hi all,
Hello,
> In the below program, i give in the hash as
>
> %TypeofNumber = ( 0b00 => Integer, 0b01 => Floating, 0b10 => Char, 0b11 =>
> Double );
*You* *have* *to* *quote* *strings*
my %TypeofNumber = ( 0b00 => 'Integer', 0b01 => 'Floating', 0b10 => 'Char',
0b
Hi all,
In the below program, i give in the hash as
%TypeofNumber = ( 0b00 => Integer, 0b01 => Floating, 0b10 => Char, 0b11 =>
Double );
Using this hash i need to priont the appropriate combination
How to do that?
Thanks and Regards,
Dharshana
On 11/13/06, Dharshana Eswaran <[EMAIL PROT
Dharshana Eswaran wrote:
> Hi all,
Hello,
> I am working on the code below
>
> use strict;
> use warnings;
>
> my $hex = "43";
>
> my $binary = unpack 'B*', pack 'H*', $hex;
>
> print "$binary\n\n";
>
> my @fields = unpack 'A2A2A4', $binary;
>
> my $i;
> printf "%-4s => %s\n", $fields[$
On Mon, 13 Nov 2006 11:35:11 +0530
"Dharshana Eswaran" <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I am working on the code below
>
> use strict;
> use warnings;
>
> my $hex = "43";
>
> my $binary = unpack 'B*', pack 'H*', $hex;
>
> print "$binary\n\n";
>
> my @fields = unpack 'A2A2A4', $bi
Hi all,
I am working on the code below
use strict;
use warnings;
my $hex = "43";
my $binary = unpack 'B*', pack 'H*', $hex;
print "$binary\n\n";
my @fields = unpack 'A2A2A4', $binary;
my $i;
printf "%-4s => %s\n", $fields[$i++], $_ foreach qw/Ext TypeofNumber
NumberingPlan/;
**OUTPUT**
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