R. Joseph Newton wrote:
>
> > > There are many references , what line number does it say
> > > is evil and which line below is that?
> >
> > Thanks for your help, I have put a -right here - in the code...
> >
> > }
> > $SQL .= "\n";
> > }
> > #-righ
Dan Anderson wrote:
> > There are many references , what line number does it say
> > is evil and which line below is that?
>
> Thanks for your help, I have put a -right here - in the code...
>
> }
> $SQL .= "\n";
> }
> #-right here--
>
On Wed, 12 Nov 2003 18:29:01 -0500, Dan Anderson wrote:
> I'm completely lost trying to debug it because the line in question is a
> }.
Well. I'm totally lost, too. There's a lot of things in the code which
you can improve to make it more fail-safe, but for now: What line are you
referring to?
On Nov 12, Dan Anderson said:
> while (my %hash = %{ shift (@columns) }) {
> ...
> }
Here is the problem. When @columns is empty, it returns undef, and you
can't do %{ +undef }. So, do this:
while (my $href = shift @columns) {
# then use $href->{...}
# or do
On Wed, 2003-11-12 at 18:30, Dan Muey wrote:
> > I am using the following code and keep getting a message that
> > says "Can't use an undefined value as a hash reference." I'm
> > completely lost trying to debug it because the line in
> > question is a }. I was wondering if any guru could spot
> I am using the following code and keep getting a message that
> says "Can't use an undefined value as a hash reference." I'm
> completely lost trying to debug it because the line in
> question is a }. I was wondering if any guru could spot some
There are many references , what line number
I am using the following code and keep getting a message that says
"Can't use an undefined value as a hash reference." I'm completely lost
trying to debug it because the line in question is a }. I was wondering
if any guru could spot some newbie idiocy in my code. I am, of course,
using strict a
