Thanks ALL! I got it.
-_-Aaron
-Original Message-
From: Etienne Marcotte [mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 13, 2001 12:25 PM
To: Aaron Shurts; [EMAIL PROTECTED]
Subject: Re: Getting rid of junk.
and while re-reading you post:
why are you using while( ($login
and while re-reading you post:
why are you using while( ($login) = $sth->fetchrow_array ())
and not while (my @row = $sth->fetchrow_array ()) ??? array is @, no?
foreach %login is a hash abnd you have login as a variable..
I think what you are looking is something like:
my $sth = $dbh->prepare
Hi Aaron,
$login =~ s!^\d{3}!!;
See also:
perldoc perlre
Cheers,
Kevin
On Thu, Dec 13, 2001 at 12:08:07PM -0800, Aaron Shurts ([EMAIL PROTECTED]) said
something similar to:
> I am not sure what to use in this case.
> I am grabbing a bunch of login information from our database. The login
> h
check out substr!
http://www.perldoc.com/perl5.6.1/pod/func/substr.html
$var= substr($var,3);
Etienne
Aaron Shurts wrote:
>
> I am not sure what to use in this case.
> I am grabbing a bunch of login information from our database. The login
> has 3 leading numbers. i.e. The value returned i
I am not sure what to use in this case.
I am grabbing a bunch of login information from our database. The login
has 3 leading numbers. i.e. The value returned is:
123login
I need to strip the 123 off and discard it. That value is unimportant
to me. Here is my pseudo-code:
while( ($login) = $
