On May 31, 7:55 am, [EMAIL PROTECTED] (David Unric) wrote:
> Based on perlref documentation arrow operator between brackets subscripts
> may be omitted so the following code is valid:
>
> @array = ( [1, 2], [3, 4] );
> $element = $array[0][0];# shorthand for $element = $array[0]->[0]
>
> Coul
On May 31, 7:55 am, [EMAIL PROTECTED] (David Unric) wrote:
> Based on perlref documentation arrow operator between brackets subscripts
> may be omitted so the following code is valid:
>
> @array = ( [1, 2], [3, 4] );
> $element = $array[0][0];# shorthand for $element = $array[0]->[0]
>
> Coul
I did suspected it would have something to do with the difference between
array and list contexts.
Your analysis seems to be correct.
Thank you for solving this puzzle :)
Regards
On 5/31/07, Chas Owens <[EMAIL PROTECTED]> wrote:
On 5/31/07, David Unric <[EMAIL PROTECTED]> wrote:
> Based on pe
On 5/31/07, David Unric <[EMAIL PROTECTED]> wrote:
Based on perlref documentation arrow operator between brackets subscripts
may be omitted so the following code is valid:
@array = ( [1, 2], [3, 4] );
$element = $array[0][0];# shorthand for $element = $array[0]->[0]
Could somebody explai
Based on perlref documentation arrow operator between brackets subscripts
may be omitted so the following code is valid:
@array = ( [1, 2], [3, 4] );
$element = $array[0][0];# shorthand for $element = $array[0]->[0]
Could somebody explain why it causes syntax error when the above rule is
