Thanks for Adriano Ferreira.Your explaination is good for me.I have known
that.
On 12/7/05, Adriano Ferreira <[EMAIL PROTECTED]> wrote:
>
> On 12/5/05, Jennifer Garner <[EMAIL PROTECTED]> wrote:
> > As we know, $::{sym} == *main::sym, it's a typeglob.
> > but what is **main::sym? and the same,what
On 12/5/05, Jennifer Garner <[EMAIL PROTECTED]> wrote:
> As we know, $::{sym} == *main::sym, it's a typeglob.
> but what is **main::sym? and the same,what is *{$glob}?thanks.
**main::sym is a syntax error, but *{*main::sym}==*main::sym.
But don't be fooled by the equality $::{sym} == *main::sym.
${*{$::{sym}}{HASH}}{name};
As we know, $::{sym} == *main::sym, it's a typeglob.
but what is **main::sym? and the same,what is *{$glob}?thanks.
On 12/6/05, Flemming Greve Skovengaard <[EMAIL PROTECTED]> wrote:
>
> Wiggins d'Anconia wrote:
> >
> > Now that you understand it, replace it with $sym-
Wiggins d'Anconia wrote:
Now that you understand it, replace it with $sym->{name} so the next
person doesn't have to ask. Unless you are using a really old Perl.
Actually that should be *sym->{name} instead of $sym->{name} ( or %sym->{name}
but that's deprecated ).
Else you get "Variable "$sy
Adriano Ferreira wrote:
> On 12/5/05, Jennifer Garner <[EMAIL PROTECTED]> wrote:
>
>>print ${*{$::{sym}}{HASH}}{name};
>
>
>>How to analyse the last sentence of that code?Thanks.
>
>
>>From "perldoc perlref"
>
>7. A reference can be created by using a special syntax, lovingly
>
On 12/5/05, Jennifer Garner <[EMAIL PROTECTED]> wrote:
> print ${*{$::{sym}}{HASH}}{name};
> How to analyse the last sentence of that code?Thanks.
>From "perldoc perlref"
7. A reference can be created by using a special syntax, lovingly
known as the *foo{THING} syntax. *foo{T
Hi,lists,
Seeing this code please:
our %sym = (
name => 'flower',
age => 23,
);
print ${*{$::{sym}}{HASH}}{name};
The result of printing is : flower.
How to analyse the last sentence of that code?Thanks.
