On Mon, Nov 30, 2009 at 5:39 PM, Anant Gupta wrote:
> I am not allowed to write to /var/www/cgi-bin/
>
> I am not the root user of my machine
> Is their any way i can try out my perl cgi programs on this machine( Red Hat
> Linux)
>
That's decided by the http server's config.
Some of httpd.conf ma
On Mon, Nov 30, 2009 at 3:46 PM, Uri Guttman wrote:
>
> what is [^()]* looking for? why couldn't () be inside the div tags?
>
Well, it's the OP's idea, not mime and YOURS.
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://
On Mon, Nov 30, 2009 at 12:40 PM, Julia Gallardo Lomeli
wrote:
> Hi,
>
> Lets say I want grep to find all class="photo">whateverElementGoesInsideTheseDivTags in index.html
>
> I am using the code below but it seems that it's not working
>
>
> grep -o "[^()]*" index.html
>
Perl's grep can do:
#
On Fri, Nov 27, 2009 at 6:32 PM, PigInACage wrote:
> Hello all.
>
> I've got a file CSV with 3 column
> name,surname,group
>
> if one of the column has got a space like
> Davide,Super Dooper,Group
> I cannot use it in a for loop
>
> for i in `cat list.csv` ; do echo $i ; done
> the result is
> Dav
On Fri, Nov 27, 2009 at 8:34 PM, Majian wrote:
> Could you explain it ?
>
> What is the meaning of the $.? And Why use the "%2" operator?
>
$. means the line number, see perldoc perlvar and look for $.
%2 means the modulus operator.
# perl -le 'print $_%2 for 0..3'
0
1
0
1
HTH.
--
To unsub
On Fri, Nov 27, 2009 at 8:03 PM, Majian wrote:
> Hi ,all:
>
> I have a problem about this :
>
> cat test:
> 12
> 23
> 34
> 45
> 56
> 67
> ...
>
> I want to become like this :
> 1223
> 3445
> 5667
> ...
>
# perl -e '
$m=<) {
chomp if $.%2;
print;
}'
1223
3445
5667
--
To unsubscribe, e-m
